def car(wheels,bodies,figures):
car_by_wheels=wheels//4
car_by_figures=figures/2
if figures//2 >= car_by_wheels and bodies >= car_by_wheels:
print(car_by_wheels)
elif car_by_wheels >= car_by_figures and bodies >= car_by_figures:
print(car_by_figures)
elif car_by_wheels >= bodies and car_by_figures >= bodies:
print(bodies)
else:
print("0")
print(car(3,29,54))我尝试了其他一些示例,代码运行良好,但我一直没有得到任何结果。如果最低要求如下:4个轮子,2个数字和一个车身,代码检查从输入的参数可以制造多少辆汽车
发布于 2020-10-25 09:06:37
您的函数没有显式返回任何内容,因此它隐式返回None。所以car(3,29,54)打印并返回None,然后打印出来。
https://stackoverflow.com/questions/64519403
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