我尝试执行的每个人的代码都在2.5.3节的"Flexible Imputation of Missing Data 2ed“一书中找到,它计算了两种估算方法的置信区间。问题是我不能重现结果,因为结果总是NaN
以下是代码
require(mice)
# function randomly draws artificial data from the specified linear model
create.data <- function(beta = 1, sigma2 = 1, n = 50, run = 1) {
set.seed(seed = run)
x <- rnorm(n)
y <- beta * x + rnorm(n, sd = sqrt(sigma2))
cbind(x = x, y = y)
}
#Remove some data
make.missing <- function(data, p = 0.5){
rx <- rbinom(nrow(data), 1, p)
data[rx == 0, "x"] <- NA
data
}
# Apply Rubin’s rules to the imputed data
test.impute <- function(data, m = 5, method = "norm", ...) {
imp <- mice(data, method = method, m = m, print = FALSE, ...)
fit <- with(imp, lm(y ~ x))
tab <- summary(pool(fit), "all", conf.int = TRUE)
as.numeric(tab["x", c("estimate", "2.5 %", "97.5 %")])
}
#Bind everything together
simulate <- function(runs = 10) {
res <- array(NA, dim = c(2, runs, 3))
dimnames(res) <- list(c("norm.predict", "norm.nob"),
as.character(1:runs),
c("estimate", "2.5 %","97.5 %"))
for(run in 1:runs) {
data <- create.data(run = run)
data <- make.missing(data)
res[1, run, ] <- test.impute(data, method = "norm.predict",
m = 2)
res[2, run, ] <- test.impute(data, method = "norm.nob")
}
res
}
res <- simulate(1000)
#Estimate the lower and upper bounds of the confidence intervals per method
apply(res, c(1, 3), mean, na.rm = TRUE)诚挚的问候
发布于 2021-03-25 11:24:24
将test.impute()最后一行中的"x"替换为tab$term == "x"
as.numeric( tab[ tab$term == "x", c("estimate", "2.5 %", "97.5 %")])https://stackoverflow.com/questions/66792429
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