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drf-yasg自定义json body
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Stack Overflow用户
提问于 2020-07-24 15:09:40
回答 1查看 1.7K关注 0票数 2

如何在ClassBased django视图中自定义drf-yasg模式?

我尝试了这部分代码,但生成的swagger不支持更改。

代码语言:javascript
复制
class CustomView(CreateAPIView):
    permission_classes = (IsAuthenticated,)
    serializer_class = CustomSerializer

    @swagger_auto_schema(request_body=openapi.Schema(
        type=openapi.TYPE_OBJECT,
        properties={
            'phone': openapi.Schema(type=openapi.TYPE_STRING, description='string'),
            'body': openapi.Schema(type=openapi.TYPE_STRING, description='string'),
        }))
    def create(self, request: Request, *args, **kwargs):
        phone = request.data.get('phone')
        body = request.data.get('body')
        ...
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回答 1

Stack Overflow用户

回答已采纳

发布于 2020-07-24 16:14:41

我找到了,下面是正确的代码:

代码语言:javascript
复制
class CustomView(CreateAPIView):
    permission_classes = (IsAuthenticated,)
    serializer_class = CustomSerializer
    http_method_names = ['post']

    @swagger_auto_schema(request_body=openapi.Schema(
        type=openapi.TYPE_OBJECT,
        properties={
            'phone': openapi.Schema(type=openapi.TYPE_STRING, description='The desc'),
            'body': openapi.Schema(type=openapi.TYPE_STRING, description='The desc'),
        }))
    def post(self, request: Request, *args, **kwargs):
        phone = request.data.get('phone')
        body = request.data.get('body')
        ...

对于IN_QUERY类型,如下所示:

代码语言:javascript
复制
class CustomListView(ListAPIView):
    permission_classes = (IsAuthenticated,)
    serializer_class = CustomSerializer
    http_method_names = ['get']

    @swagger_auto_schema(manual_parameters=[
        openapi.Parameter('obj_id', openapi.IN_QUERY,
                          type=openapi.TYPE_STRING),
    ])
    def get(self, request, *args, **kwargs):
        obj_id = self.request.DATA.get('obj_id')
票数 8
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/63068565

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