如何比较Invoke-Sqlcmd的结果？

Question

目标是比较数据库查询结果。但是，在Invoke-Sqlcmd的结果上使用Compare-Object并不表示不同事物的粒度级别。我怎么才能做到这一点？我必须手动逐个字段进行比较吗？

InputObject         SideIndicator
-----------         -------------
System.Data.DataRow <=
System.Data.DataRow <=
System.Data.DataRow <=
...

结果是由以下代码生成的。

$query = @"
SELECT *
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = '$TableName'
AND TABLE_SCHEMA = '$Schema'
"@
$t1 = Invoke-Sqlcmd -ServerInstance $SqlInstance -Database $Database -Query $query

$query2 = @"
SELECT *
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = '$TableName2'
AND TABLE_SCHEMA = '$Schema2'
"@
$t2 = Invoke-Sqlcmd -ServerInstance $SqlInstance2 -Database $Database2 -Query $query2

$t1.GetType()
$t1[0].GetType()
$t1[0] | fl * -Force
$t2[0] | fl * -Force
Write-Information -MessageData "comparing both query results"
Compare-Object -ReferenceObject $t1 -DifferenceObject $t2

Write-Information -MessageData "comparing first elements of the array"
Compare-Object -ReferenceObject $t1[0] -DifferenceObject $t2[0]

Write-Information -MessageData "comparing first element members"
Compare-Object -ReferenceObject ($t1[0]).COLUMN_NAME -DifferenceObject ($t2[0]).COLUMN_NAME
$query = @"
SELECT *
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = '$TableName'
AND TABLE_SCHEMA = '$Schema'
"@
$t1 = Invoke-Sqlcmd -ServerInstance $SqlInstance -Database $Database -Query $query

$query2 = @"
SELECT *
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = '$TableName2'
AND TABLE_SCHEMA = '$Schema2'
"@
$t2 = Invoke-Sqlcmd -ServerInstance $SqlInstance2 -Database $Database2 -Query $query2

$t1.GetType()
$t1[0].GetType()
$t1[0] | fl * -Force
$t2[0] | fl * -Force
Write-Information -MessageData "comparing both query results"
Compare-Object -ReferenceObject $t1 -DifferenceObject $t2

Write-Information -MessageData "comparing first elements of the array"
Compare-Object -ReferenceObject $t1[0] -DifferenceObject $t2[0]

Write-Information -MessageData "comparing first element members"
Compare-Object -ReferenceObject ($t1[0]).COLUMN_NAME -DifferenceObject ($t2[0]).COLUMN_NAME

Answer 1

Compare-Object ($t1 | ConvertTo-CSV) ($t2 | ConvertTo-CSV) | Format-List

如果生成的CSV不是太宽而无法显示在屏幕上，请移除| Format-List。