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社区首页 >问答首页 >如何创建用于测试的Microsoft.AspNetCore.Http.HttpRequest实例?

如何创建用于测试的Microsoft.AspNetCore.Http.HttpRequest实例?
EN

Stack Overflow用户
提问于 2020-11-02 00:52:41
回答 1查看 1K关注 0票数 4

我希望创建一个包含填充数据的HttpRequest实例,以便测试方法。

我需要将Microsoft.AspNetCore.Http.HttpRequest作为参数传递给函数。

我如何实例化它?

代码语言:javascript
复制
[Route("/summary/{id}")]
public IActionResult Account(int id)
{
   var summary = RequestHelper.ParseRequest(Request);
}

选项来自https://github.com/louthy/language-ext

代码语言:javascript
复制
public static Option<SummaryRequest> ParseRequest(HttpRequest request)
{
    if (request== null)
    {
        var query = request.Query;
  
        var result = new SummaryRequest();
    
        var locations = ExtractData(query, "location");
        var categories = ExtractData(query, "categories[]");
        var titles = ExtractData(query, "titles");
    
    }
}
    
public static Option<SummaryRequest> ParseRequest(HttpRequest request)
{
    if (request== null)
    {
        var query = request.Query;
            
        var result = new SummaryRequest();
            
        var locations = ExtractData(query, "location");
        var categories = ExtractData(query, "categories[]");
        var titles = ExtractData(query, "titles");
    }
           
    return new SummaryRequest();
}

public static Either<Exception, string[]> ExtractData(IEnumerable<KeyValuePair<String, StringValues>> query, string filter)
{
    try
    {
        return query.First(x => x.Key.ToLower() == filter).Value.ToString().Split(',').ToArray();
    }
    catch (Exception ex)
    {
         return ex;
    }
} 

单元测试示例

代码语言:javascript
复制
 [TestMethod]
 [TestCategory(Test.RequestParser)]
 public void ParseRequest_WithHttpRequest_ReturnResultOnSuccess()
 {            
    // var request = this doesn't compile I need an instance of 
    //                 Microsoft.AspNetCore.Http.HttpRequest
        
     var result = Helper.ParseRequest(request);
 }
EN

回答 1

Stack Overflow用户

发布于 2021-07-20 18:24:31

您可以使用Request property of DefaultHttpContext。这有点复杂,因为你必须单独指定很多属性(与WebRequest.Create相比),但下面的方法对我来说很有效:

代码语言:javascript
复制
var httpContext = new DefaultHttpContext();
httpContext.Request.Method = "POST";
httpContext.Request.Scheme = "http";
httpContext.Request.Host = new HostString("localhost");
httpContext.Request.ContentType = "application/json";
var stream = new MemoryStream();
var writer = new StreamWriter(stream);
await writer.WriteAsync("{}");
await writer.FlushAsync();
stream.Position = 0;
httpContext.Request.Body = stream;
票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/64634428

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