ngrx简单状态归约器

Question

angular和ngrx的新手，跟随文档，

我将基本示例修改为以下内容：

行为

export const increment = createAction('[Counter Component] Increment');
export const decrement = createAction('[Counter Component] Decrement');
export const reset = createAction('[Counter Component] Reset');

减速机

export const initialState = {
  num: 0
};

const _counterReducer = createReducer(initialState,
  on(increment, state => ({ num: state.num + 1})),
  on(decrement, state => ({ num: state.num - 1})),
  on(reset, state => ({ num: 0 })),
);

模块

StoreModule.forRoot({ count: counterReducer })

组件

TS

count$: Observable<IState>;

constructor(private store: Store<{ count: IState }>) {
    this.count$ = store.pipe(select('count'));
}

HTML

<p> count$.num | async </p>

Model.ts

export interface IState {
  num: number
}

看起来我错过了一些微不足道的东西。

StackBlitz：https://stackblitz.com/edit/angular-72vhrz

Answer 1

<p> (count$| async).name </p>

首先必须在上明显地使用async管道，这将展开它的值，您可以访问它。