如果没有找到给定的job_title,我会尝试从我的数据表中删除一行,但我得到的是table.row(...).delete is not a function
$(document).ready( function () {
var keywords = ['aslr', 'ida pro', 'gdb', 'windbg', 'immunity debugger', 'boofuzz', 'peach fuzzer', 'winafl', 'python', 'assembly', 'penetration testing', 'exploits', 'metasploit', 'metasploit framework', 'ethical hacker', 'pentest', 'computer security', 'hacking', 'oscp', 'osce', 'osee', 'penetration testing', 'offensive security', 'mitre att&ck', 'vulnerability research', 'vulnerability researcher', 'fuzzing', 'clang', 'llvm', 'address sanitizer', 'afl', 'fuzzers','penetration tester']
var job_title = ['penetration tester','penetration testing', 'offensive security', 'vulnerability researcher','software','security','developer','ethical hacker','cyberSécurité','threat','it Security','application security','information security','security engineer','product security','cyber security','software engineer']
var table = $('#example').DataTable({
responsive: true,
"ajax": {
"url": "/index_get_data",
"dataType": "json",
"dataSrc": "jobs",
"contentType":"application/json"
},
columnDefs: [{
targets: 0,
render: function (data,row) {
for (var i = 0; i < job_title.length; i += 1) {
if (data.indexOf(job_title[i])) {
console.log("FOUND")
}else{
table.row( this ).delete();
}
}
}
},{
targets: 4,
render: function (data) {
for (var i = 0; i < keywords.length; i += 1) {
if (data.indexOf(keywords[i])) {
return "<span class='label label-success'>FOUND</span>";
}
}
return "<span class='label label-danger'>NOT_FOUND</span>";
}
},{
targets: 5,
render: function (data) {
return '<a href="'+data+'">Link</a>'
}
}],
"columns": [
{"data": "job_title"},
{"data": "company"},
{"data": "city"},
{"data": "date"},
{"data": "job_description"},
{"data": "url"},
]
});
setInterval( function () {
table.ajax.reload( null, false );
}, 30000 );
} );发布于 2019-10-16 16:52:36
https://stackoverflow.com/questions/58409208
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