保留圆形分割的新列

Question

data.frame(id = c(1,2,3), num = c(123, 23, 3210))

如何将列num除以30并将其四舍五入为最高值，然后在数据帧中创建新列

输出示例

data.frame(id = c(1,2,3), num = c(123, 43, 3210), round = c(5, 1, 107))

Answer 1

您可以使用ceiling

x$round <- ceiling(x$num / 30)
x
#  id  num round
#1  1  123     5
#2  2   23     1
#3  3 3210   107

Answer 2

library(dplyr)
df %>% mutate(round = ceiling(num/30))
  id  num round
1  1  123     5
2  2   23     1
3  3 3210   107