如何分别打印CLI项目的名称和URL

Question

我正在构建一个吉他浏览CLI。我将吉他的名称和URL放在一个散列数组中：

def self.get_electric
        doc = Nokogiri::HTML(open("https://reverb.com/c/electric-guitars"))

        electrics = []
        counter = 0

        while counter < doc.css("h2:contains('Popular Electric Guitars')+div.overflowing-row_items    ul.tiles.tiles--single-row.tiles--grow.tiles--three-wide li.tiles_tile").length
        electric = {
            name: doc.css("h2:contains('Popular Electric Guitars')+div.overflowing-row_items ul.tiles.tiles--single-row.tiles--grow.tiles--three-wide li.tiles_tile")[counter].text,
            url: doc.css("h2:contains('Popular Electric Guitars')+div.overflowing-row_items ul.tiles.tiles--single-row.tiles--grow.tiles--three-wide li.tiles_tile a.marketing-callout__inner")[counter]["href"]
        }
        counter += 1
        electrics << electric
        end
        electrics
    end

    def self.get_acoustic
        doc = Nokogiri::HTML(open("https://reverb.com/c/acoustic-guitars"))

        acoustics = []
        counter = 0

        while counter < doc.css("h2:contains('Popular in Acoustic Guitars')+div.overflowing-row_items ul.tiles.tiles--single-row.tiles--grow.tiles--three-wide li.tiles_tile").length
            acoustic = {
                name: doc.css("h2:contains('Popular in Acoustic Guitars')+div.overflowing-row_items ul.tiles.tiles--single-row.tiles--grow.tiles--three-wide li.tiles_tile")[counter].text,
                url: doc.css("h2:contains('Popular in Acoustic Guitars')+div.overflowing-row_items ul.tiles.tiles--single-row.tiles--grow.tiles--three-wide li.tiles_tile a.marketing-callout__inner")[counter]["href"]
            }
            counter += 1
            acoustics << acoustic
        end
        acoustics
    end

在我的CLI类中，当用户输入“电动”或“声学”时，他们会得到名称和URL。以下是其中一种方法：

while (input = gets.strip.downcase) != 'exit'

            case input
            when "electric"
               electrics = HiStrung::Scraper.get_electric
               electrics.each do |electric|
                puts "#{electric.name}"
               end

当我放入.name时，我得到：

/Users/tlreigns/RoyalTerminal/hi_strung/lib/hi_strung/cli.rb:43:in `block in menu': undefined method `name' for #<Hash:0x00007fab93b96a40> (NoMethodError)

但是如果我只做#{electric}，我会得到：

{:name=>"Fender Telecaster", :url=>"https://reverb.com/marketplace/electric-guitars?query=telecaster"}
{:name=>"Gibson Les Paul", :url=>"https://reverb.com/marketplace?query=les%20paul"}
{:name=>"Fender Stratocaster", :url=>"https://reverb.com/marketplace/electric-guitars?query=stratocaster"}
{:name=>"Gibson SG", :url=>"https://reverb.com/marketplace?query=sg"}
{:name=>"Fender Jazzmaster", :url=>"https://reverb.com/marketplace?query=jazzmaster"}

如何分别获取名称和URL？

Answer 1

electrics的每个元素都是一个散列。您只需要值，而不是键-值对。

所以，我相信你只需要

puts electric[:name]

和

puts electric[:url]

(没有字符串插值将会工作，正如Amit Patel在注释中指出的那样)，以获得所需的输出。