我是一个初学者在使用数据编织转换,我正在尝试编写一个Mule 4数据编织表达式来转换输入JSON到输出XML格式,我有一个有效载荷在JSON格式,我想把它转换成一个特定的XML格式,下面是实际的JSON输出XML
产品id( XML )标签来自JSON的PBSI__Item__r标签的name属性,XML中的分配值来自PBSI__Inventory__r标签的name属性
JSON:
[
{
"PBSI__Item__r": {
"Id": null,
"type": "PBSI__PBSI_Item__c",
"Name": "116065"
},
"PBSI__Inventory__r": [
{
"Id": null,
"type": "PBSI__PBSI_Inventory__c",
"PBSI__Real_Quantity__c": "13.0"
}
],
"PBSI__Location__r": {
"Id": null,
"type": "PBSI__PBSI_Location__c",
"Name": "OB043"
},
"Id": null,
"type": "PBSI__Lot__c"
},
{
"PBSI__Item__r": {
"Id": null,
"type": "PBSI__PBSI_Item__c",
"Name": "116066"
},
"PBSI__Inventory__r": [
{
"Id": null,
"type": "PBSI__PBSI_Inventory__c",
"PBSI__Real_Quantity__c": "1.0"
}
],
"PBSI__Location__r": {
"Id": null,
"type": "PBSI__PBSI_Location__c",
"Name": "OA011"
},
"Id": null,
"type": "PBSI__Lot__c"
}
]输出XML:
<?xml version='1.0' encoding='UTF-8'?>
<inventory xmlns="http://www.demandware.com/xml/impex/inventory/2007-05-31">
<inventory-list>
<header list-id="Hastens_Inventory">
<default-instock>false</default-instock>
<use-bundle-inventory-only>false</use-bundle-inventory-only>
</header>
<records>
<record product-id="116065">
<allocation>13</allocation>
<allocation-timestamp>2019-04-24T07:09:51.954Z</allocation-timestamp>
</record>
<record product-id="116066">
<allocation>1</allocation>
<allocation-timestamp>2019-04-24T07:09:51.965Z</allocation-timestamp>
</record>
</records>
</inventory-list>
</inventory>发布于 2020-11-11 03:30:26
这应该会帮助你找到一个解决方案,也可以学习如何做到这一点,我还没有给出一个完整的解决方案,所以你可以把它作为一个起点(几乎完成了80% )。
此外,要包含名称空间,请访问链接https://docs.mulesoft.com/mule-runtime/4.3/dataweave-cookbook-include-xml-namespaces
{
inventory:{
inventorylist: {
header @("list-id":"Hastens_Inventory"):
{
"default-instock":false,
"use-bundle-inventory-only":false
},
records: {(payload map
{
record @("product-id": $.PBSI__Item__r.Name): {
allocation: $.PBSI__Inventory__r[0].PBSI__Real_Quantity__c,
"allocation-timestamp": now()
}
})}
}
}
}https://stackoverflow.com/questions/64775112
复制相似问题