遍历JSON数据并使用NodeJS查找可能的组合

Question

我有以下JSON数据。如何遍历JSON数据并根据输入的名称找到可能的组合？

维度数组：

[
  {"value":"zabbixPy-API","name":"ApiName"}, 
  {"value":"qa","name":"Stage"}
]

示例:我提供了以下可能存在于Dimensions数组中的[D1

ApiId
ApiName
Stage    

如何构造变量key的示例。

function test(name) {
  if (Dimensions.name[0] && Dimensions.name[1] && Dimensions.name[2]) {
    key = Dimensions.name[0].value + "_" + Dimensions.name[1].value + "_" + Dimensions.name[2].value;
  } else if (Dimensions.name[0] && Dimensions.name[1]) {
    key = Dimensions.name[0].value + "_" + Dimensions.name[1].value;
  } else if (Dimensions.name[0]) {
    key = Dimensions.name[0].value;
  } else {
    key = Metrics[].MetricName;
  }

  return key;
}

test(uniqueMetricsArray);

但在我的例子中，uniqueMetricsArray长度可能是4或5，所以我不想写所有可能的if条件。有没有一种方法可以根据输入名称数组的长度遍历，找到它可能存在的所有可能的组合，并构造变量键？

因此维度数组可以是：

 ApiName + Stage + ApiId
 ApiName + Stage
 ApiId + Stage
 ApiId + ApiName  
 Stage
 ApiId

Full Json Data:

const jsondata = {
  AlarmName: "Zabbix PY 5XX - By Stage QA",
  AlarmDescription: null,
  AWSAccountId: "123456",
  NewStateValue: "ALARM",
  NewStateReason:
    "Threshold Crossed: 1 out of the last 1 datapoints [1.0 (06/11/21 12:16:00)] was greater than or equal to the threshold (1.0) (minimum 1 datapoint for OK -> ALARM transition).",
  StateChangeTime: "2021-11-06T12:17:43.811+0000",
  Region: "Asia Pacific (Mumbai)",
  AlarmArn: "arn:aws:cloudwatch:ap-south-1:123456:alarm:Zabbix PY 5XX - By Stage QA",
  OldStateValue: "INSUFFICIENT_DATA",
  Trigger: {
    MetricName: "5XXError",
    Namespace: "AWS/ApiGateway",
    StatisticType: "Statistic",
    Statistic: "MINIMUM",
    Unit: null,
    Dimensions: [
      { value: "zabbixPy-API", name: "ApiName" },
      { value: "qa", name: "Stage" },
    ],
    Period: 60,
    EvaluationPeriods: 1,
    ComparisonOperator: "GreaterThanOrEqualToThreshold",
    Threshold: 1,
    TreatMissingData: "- TreatMissingData: missing",
    EvaluateLowSampleCountPercentile: "",
  },
};

console.log(uniqueMetricsArray):的输出

ApiId
ApiName
Stage    

这就是实际的if条件可能的样子。我只是在上面的例子中缩短了它：

  if (sns.Trigger.Dimensions.find(dimension => dimension.name === name[0]) && sns.Trigger.Dimensions.find(dimension => dimension.name === name[1]) && sns.Trigger.Dimensions.find(dimension => dimension.name === name[2]) ) {
    var key = sns.Trigger.Dimensions.find(dimension => dimension.name === name[0]).value  + '_' + sns.Trigger.Dimensions.find(dimension => dimension.name === name[1]).value + '_' + sns.Trigger.Dimensions.find(dimension => dimension.name === name[2]).value
  }  

Answer 1

好的。这是基于this answer to generate all combinations的，只适用于数组(假设您的字符串没有NUL字符)。

function generate(array) {
  if (!array.includes("")) array = [...array, ""]; // need the empty string to generate all combinations
  return array
    .flatMap((v, i) => array.slice(i + 1).map((w) => `${v}\x00${w}`))
    .map((atom) => atom.split("\x00").filter(Boolean));
}

console.log(generate(["ApiId", "ApiName", "Stage"]));

输出

[
  [ 'ApiId', 'ApiName' ],
  [ 'ApiId', 'Stage' ],
  [ 'ApiId' ],
  [ 'ApiName', 'Stage' ],
  [ 'ApiName' ],
  [ 'Stage' ]
]