如何在Python中将此字符串转换为多维列表？

Question

我有下一个string

string = 'tuned     1372                root    6u      REG                8,3      4096  102029349 /tmp/ffiabNswC (deleted)\ngmain     1372 2614           root    6u      REG                8,3      4096  102029349 /tmp/ffiabNswC (deleted)\n'

我需要将string的每个元素放入list1[0][..]中，但当我看到新行'\n‘时，我必须将接下来的元素放入list1[1][..]中

多维列表，如下所示：

list1 = [["tuned", "1372", "root", "6u", "REG", "8,3", "4096", "102029349", "/tmp/ffiabNswC", "(deleted)"], 
         ["gmain", "1372", "2614", "root", "6u", "REG", "8,3", "4096", "102029349", "/tmp/ffiabNswC", "(deleted)"]]

我用split做了这件事，但它把我都放在了同一个维度上。

Answer 1

首先拆分一行(以获得行)，然后按空格拆分每个元素(以获得每列)：

data = "tuned 1372 root 6u REG 8,3 4096 102029349 /tmp/ffiabNswC (deleted)\ngmain 1372 2614 root 6u REG 8,3 4096 102029349 /tmp/ffiabNswC (deleted)\n"

parsed = [elements.split() for elements in data.strip().split("\n")]  # `strip()` removes the last whitespace so we don't get blank elements

print(parsed)

# [['tuned', '1372', 'root', '6u', 'REG', '8,3', '4096', '102029349', '/tmp/ffiabNswC', '(deleted)'], ['gmain', '1372', '2614', 'root', '6u', 'REG', '8,3', '4096', '102029349', '/tmp/ffiabNswC', '(deleted)']]

Answer 2

以下函数将为您完成此操作：

f = lambda list: [sublist.split(' ') for sublist in list.split('\n')]

只要通过f(string)调用即可。

另外，如果你不想在你的子列表中有任何空条目，你可以这样做

f = lambda list: [sublist.split(' ') for sublist in list.split('\n') if sublist]

Answer 3

输入：-

string = 'tuned 1372 root 6u REG 8,3 4096 102029349 /tmp/ffiabNswC 
(deleted)\ngmain 1372 2614 root 6u REG 8,3 4096 102029349 /tmp/ffiabNswC 
(deleted)\n'

代码：-只需写

 mylist=string.split()

输出：-

[tuned
 1372
 root
6u
REG
8,3
4096
102029349
/tmp/ffiabNswC
(deleted)
gmain
1372
2614
root
6u
REG
8,3
4096
102029349
/tmp/ffiabNswC
(deleted)]