JS:按日期和时间排序数组

Question

[09.02.2017 - 10:40:06][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:24:26][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:29:24][NOTICE] - Start looping through invoices from Teamleader..

以下是生成上述输出的代码：

var data = allText.split("\n");
for(var i = 0, len = data.length; i < len; i++){
   console.log(data[i]);
}

是否可以在给定的日期和时间对数组进行排序？

下面是一个示例，说明了它应该是什么样子：

[09.02.2017 - 10:40:06][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:29:25][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:24:26][NOTICE] - Start looping through invoices from Teamleader..

Answer 1

在撰写本文时，其他解决方案要么不完整，要么包含错误。特别是，accepted answer by rakwaht将日期排序为字符串，这会给出不正确的结果。

您可以使用正则表达式和Date构造函数从一行中提取和解析日期。从那里开始，只需对包含行的数组进行排序：

​

const data = `
[09.02.2017 - 10:40:06][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:24:26][NOTICE] - Start looping through invoices from Teamleader..
[08.02.2017 - 10:29:24][NOTICE] - Start looping through invoices from Teamleader..`
  .trim().split('\n')

function dateFromLine(line) {
  const result = /^\[(.*?)\]/.exec(line)
  const date = result[1].replace("-", "")
  return new Date(date)
}

function compareLinesByDate(a, b) {
  return dateFromLine(b) - dateFromLine(a)
}

data.sort(compareLinesByDate)
console.log(data.join('\n'))

​

请注意，此代码假定每一行都以这种方式格式化。要使其更加健壮，还需要做更多的工作。

Answer 2

您可以使用排序函数对数组进行排序，在该函数中，您可以指定应根据哪个基础对数组进行排序：

下面是一个符合您需求的示例：

​

var data = [
"[09.02.2017 - 10:40:06][NOTICE] - Start looping through invoices from Teamleader]",
"[08.02.2017 - 10:24:26][NOTICE] - Start looping through invoices from Teamleader]",
"[08.02.2017 - 10:29:24][NOTICE] - Start looping through invoices from Teamleader]"
];
data.sort(
    function(a, b){ 
         // a and b are two elements in the list that are supposed to be compared
         var a_date = a.substring(1, 22); //take only date from string
         var b_date = b.substring(1, 22); //take only date from string
         // We compare those strings to order it.
         if ( a_date < b_date )
            return 1;
         if ( a_date > b_date  )
            return -1;
         return 0;
    }
);
 console.log(data);

​

您可以在JS中找到一些对here函数的引用

Answer 3

您可以在数组上使用函数sort()和一个比较函数来比较日期。我不知道你在试着比较什么，但这里有一个简单的例子。

[/*...*/].sort(function(a, b){
    //here a and b stand for your dates. you will need to adjuste your code to  make it works since we have very little information about it.
    return Date.compare(a, b);
});