获取对象中属性的最大值

Question

我正在尝试获取对象中所有wins属性的最大值。以下是该对象的简短示例，我正在尝试获取wins属性的最大值，即11。

var coach_wins = {
  "player1": [
    {
      year: 2015,
      wins: 6
    },
    {
      year: 2016,
      wins: 6
    }
  ],
  "player2": [
    {
      year: 2015,
      wins: 11
    },
    {
      year: 2016,
      wins: 6
    }
  ]
};

目前我正在计算对象的长度，然后使用for循环遍历对象并获得键：

coach_wins[Object.keys(coach_wins)[i]];

然后再次执行此操作，并存储每个wins值的值；

有没有更有效的方法？

谢谢。

Answer 1

​

var coach_wins = {
  "player1": [
    {
      year: 2015,
      wins: 6
    },
    {
      year: 2016,
      wins: 6
    }
  ],
  "player2": [
    {
      year: 2015,
      wins: 11
    },
    {
      year: 2016,
      wins: 6
    }
  ]
};

var max = Object.values(coach_wins) //get all the values of the object
  .reduce(function(largest, player){ //reduce the max for all player
    return player.reduce(function(largest, record){ //reduce the max for each player
      return (largest > record.wins ? largest : record.wins);
    }, largest);
  }, 0);

console.log(max);

​

Answer 2

这个怎么样？

Object.values(coach_wins).reduce(
  (result, player) => Math.max(result, player.reduce(
    (wins, winsPerYear) => Math.max(wins, winsPerYear.wins)
  , 0))
, 0); // --> 11

Answer 3

如果player的各个数组总是包含2，我想这很好，但是如果它可以改变，你可以这样做。一小段代码，但不会把你放在异常中

function getMaxWins(){
    var maxWins = 0;
    for (var curPlayer in coach_wins) {

        //checking whether is it contains records
        var playerRecords = coach_wins[curPlayer];

        if(playerRecords){
            playerRecords.forEach(function (playerRecord_) {
                if(maxWins < playerRecord_.wins) maxWins = playerRecord_.wins;
            });
        }
    }
    return maxWins;
}

console.log(getMaxWins());