如何在Python中多次获取两个标记之间的子字符串？

Question

我有以下代码：

s = '''alt="Thunder Force"/>ehkjehkljhiflealt="Godzilla vs. Kong"/>'''

for i in s:
    start = s.find('alt="') + len('alt="')
    end = s.find('"/>')
    substring = s[start:end]
    print(substring)

但它只打印了“雷霆之力”很多次。我希望它能找到“雷霆之力”和“哥斯拉vs.孔”，并将这两个分别打印一次。怎么做？

Answer 1

您可以使用regex

import re
s = '''alt="Thunder Force"/>ehkjehkljhiflealt="Godzilla vs. Kong"/>'''
x = re.findall(r'alt="(.*?)"/>', s)
print(x)

输出

['Thunder Force', 'Godzilla vs. Kong']

Answer 2

使用regex和re.findall()

s = '''alt="Thunder Force"/>ehkjehkljhiflealt="Godzilla vs. Kong"/>'''

print(re.findall(r'(?<=alt\=").*?(?="/>)', s))
#['Thunder Force', 'Godzilla vs. Kong']

Answer 3

下面是一个非正则表达式的解决方案，它看起来更像我认为您试图通过发布的尝试实现的目标：

start = 0
while True:
    start = s.find('alt="', start)
    if start == -1:
        break
    start += len('alt="')
    end = s.find('"/>', start)
    if end == -1:
        break
    substring = s[start:end]
    start = end
    print(substring)