如何获得网络响应，即使状态码不是200

Question

我使用API进行登录，如果登录成功，则返回代码200并响应。如果不正确的电子邮件或密码将返回带有json对象包含错误的代码401，问题是我希望获得网络响应，即使请求代码不等于200，如图所示

​

但是volley抛出异常BasicNetwork.performRequest: Unexpected response code 401

以下是我的代码

public interface OnResponse{
    void onResponse(JSONObject response) throws Exception;
    void onErrorResponse(VolleyError volleyError);
}//OnResponse



public static void newRequest(Context context, String url, final Map<String, String>params, final OnResponse onResponse){
    // - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
    // - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

    RequestQueue queue = Volley.newRequestQueue(context);
    //
    //onErrorResponse()
    //onResponse()
    StringRequest stringRequest = new StringRequest(Request.Method.POST, url, response -> {
        // - - - - - - - - - - - - - - - - - - - - -
        try {
            JSONObject object = new JSONObject(response);
            onResponse.onResponse(object);
        } catch (Exception e) {
            Log.e(TAG, "FLAG-1");
            e.printStackTrace();
        }
        // - - - - - - - - - - - - - - - - - - - - -
    }, error -> {
        Log.e(TAG, "FLAG-2");
        onResponse.onErrorResponse(error);
    }){
        @Override
        protected VolleyError parseNetworkError(VolleyError volleyError) {
            volleyError.printStackTrace();
            Log.e("zxc", volleyError.getMessage()+"");
            Log.e("zxc", volleyError.getLocalizedMessage()+"");
            return super.parseNetworkError(volleyError);
        }
    };
    //
    stringRequest.setParams(params);
    stringRequest.setShouldCache(false);
    queue.add(stringRequest);
    // - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
    // - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
}//newRequest()`

Answer 1

VolleyError具有networkResponse属性，它包含响应。

这是一个例子：String response = new String(error.networkResponse.data);

Answer 2

只需覆盖newRequest()方法中的parseNetworkResponse，如下所示

StringRequest request = new StringRequest(Method.GET,
            <your url>,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    //handle response
                }
            },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {
                    //handle error
                }
            }) {

        @Override
        protected Response<String> parseNetworkResponse(NetworkResponse response) {
            int mStatusCode = response.statusCode;
            return super.parseNetworkResponse(response);
        }
    };

Answer 3

您可以从VolleyError中提取响应数据。

@Override
public void onErrorResponse(VolleyError error) {
   NetworkResponse networkResponse = error.networkResponse;
   if (networkResponse != null && networkResponse.data != null) {
   String jsonError = new String(networkResponse.data);
   // Print Error!
    }
 }