遍历对象数组，查找包含2个值的对象

Question

我目前有一个数组，看起来像这样：

var array = [
      {
        "name": "a",
        "age": 1,
        "siblings": 3
      },
      {
        "name": "b",
        "age": 3,
        "siblings": 5
      },
      {
        "name": "a",
        "age": 1,
        "siblings": 2
      }
]

我想创建一个接受两个值的函数，并返回一个包含匹配这两个值的对象的新数组。

var name = "a";
var age = 1;
someFunction(name, age);

并返回如下所示的内容：

newArray = [
      {
        "name": "a",
        "age": 1,
        "siblings": 3
      },
      {
        "name": "a",
        "age": 1,
        "siblings": 2
      }

]

我尝试过使用filter方法和reduce方法，但没有成功。如果有人能帮助我或为我指明正确的方向，我将不胜感激。

​

var array = [
      {
        "name": "a",
        "age": 1,
        "siblings": 3
      },
      {
        "name": "b",
        "age": 3,
        "siblings": 5
      },
      {
        "name": "a",
        "age": 1,
        "siblings": 2
      }
]

 var result = array.filter(function(obj) {
           return obj.name === "a" && obj.age === 1;
           });
    return result[0];
 }
console.log(result);

​

Answer 1

您可以使用包含所需键/值对的数组进行搜索。

使用Array#every检查谓词，然后使用Array#filter。

​

var array = [{ name: "a", age: 1, siblings: 3 }, { name: "b", age: 3, siblings: 5 }, { name: "a", age: 1, siblings: 2 }],
    search = [['name', 'a'], ['age', 1]],
    result = array.filter(object => search.every(([key, value]) => object[key] === value));

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

​

Answer 2

以下是您的工作函数

function someFunction (name, age) {
    return array.filter(val => val.name == name && val.age == age)
}

Answer 3

在Array#filter回调中，只需将当前元素的name & age与您传入的参数进行比较即可。

​

var array = [{"name":"a","age":1,"siblings":3},{"name":"b","age":3,"siblings":5},{"name":"a","age":1,"siblings":2}]
var name = "a";
var age = 1;
function someFunction(name, age){
 return array.filter((obj) => obj.name === name && obj.age === age)
}
console.log(someFunction(name, age));

​

您也可以使用Array#reduce。只需将匹配的对象添加到累加器数组中并返回它。

​

var array = [{"name":"a","age":1,"siblings":3},{"name":"b","age":3,"siblings":5},{"name":"a","age":1,"siblings":2}]
var name = "a";
var age = 1;
function someFunction(name, age){
 return array.reduce((acc, obj) => {
   if(obj.name === name && obj.age === age) 
     acc.push(obj);
   return acc;
 }, []);
}
console.log(someFunction(name, age));

​