Repl.it (P5.js)中的While语句崩溃选项卡

Question

我27号有一个项目要交，我遇到了一个问题。每当我启动我的程序时，Repl.it就会崩溃。如果你看看我的代码，在第42行：

//getting a number that isnt the players door or the prize door
  while ((randomDoor2 == prizeDoor) || (randomDoor2 == randomDoor)) {
    setTimeout(
      function(){ 
        randomDoor2 = Math.round(random(1,3));
      }, 
      10000);
  }

有一个while循环。注释掉它可以使代码完美地工作，没有延迟。

我不知道我应该尝试做什么。

它可能不是我的while，所以这是我的整个script.js：

var chance; // swap | dont swap
var prizeDoor;
var randomDoor;
var randomDoor2;
var randomDoor3;
var decide;

function setup() {
  chance = 50;
  createCanvas(1000,1000);
}

function draw() {
 //setting up round

  prizeDoor = Math.round(random(1,3));

  //choosing first door

  console.log("[1] [2] [3]");
  randomDoor = Math.round(random(1,3));

  //showing user the door AI picks
var chance = 50; // swap | dont swap
var prizeDoor;
var randomDoor;
var randomDoor2;
var randomDoor3;
var decide;

function setup() {
  chance = 50;
  createCanvas(1000,1000);
}

function draw() {
 //setting up round

  prizeDoor = Math.round(random(1,3));

  //choosing first door

  console.log("[1] [2] [3]");
  randomDoor = Math.round(random(1,3));

  //showing user the door AI picks

  if (randomDoor == 1) {
    console.log(" ^");
    console.log(" |");
  } else if (randomDoor == 2) {
    console.log("     ^");
    console.log("     |");
  } else {
    console.log("         ^");
    console.log("         |");
  }

  console.log("AI chooses door #" + randomDoor + ".");

  //revealing a door

  //getting a number that isnt the players door or the prize door
  while ((randomDoor2 == prizeDoor) || (randomDoor2 == randomDoor)) {
    setTimeout(
      function(){ 
        randomDoor2 = Math.round(random(1,3));
      }, 
      10000);
  }

  //showing this to the user
  console.log("");
  console.log("Door #" + randomDoor2 + " does not have the prize.");

  //having the computer make a desicion
  if (random(0,100) < chance) {
    decide = "swap doors.";
    while ((randomDoor3 !== randomDoor2) || (randomDoor3 !==  randomDoor)) {
      randomDoor3 = Math.round(random(1,3));
    }
  } else {
    decide = "keep the current door.";
  }

  //letting the user know of the computer's desicion
  console.log("");
  console.log("The AI chose to " + decide);

  // figuring out if the AI won
  if (randomDoor3 == prizeDoor || randomDoor == prizeDoor) {

    console.log("AI won!");

    if (decide == "swap doors.") {
      chance -= 5;
    } else {
      chance += 5;
    }
  } else {

    console.log("AI lost.");

    if (decide == "swap doors.") {
      chance += 5;
    } else {
      chance -= 5;
    }
  }
}

我希望while语句找到的门既不是所选的门，也不是有奖品的门，但它却崩溃了。

Answer 1

我想通了。这实际上非常简单，只需更改一些运算符即可。下面是最后一段代码：

var chance = 50; // swap | dont swap
var prizeDoor;
var randomDoor;
var randomDoor2;
var randomDoor3;
var decide;

function setup() {
  chance = 50;
  createCanvas(1000,1000);
}

function draw() {
 //setting up round

  prizeDoor = Math.round(random(1,3));

  //choosing first door

  console.log("[1] [2] [3]");
  randomDoor = Math.round(random(1,3));

  //showing user the door AI picks

  if (randomDoor == 1) {
    console.log(" ^");
    console.log(" |");
  } else if (randomDoor == 2) {
    console.log("     ^");
    console.log("     |");
  } else {
    console.log("         ^");
    console.log("         |");
  }

  console.log("AI chooses door #" + randomDoor + ".");

  //revealing a door

  //getting a number that isnt the players door or the prize door
  while ((randomDoor2 == prizeDoor) || (randomDoor2 == randomDoor)) {
    setTimeout(
      function(){ 
        randomDoor2 = Math.round(random(1,3));
      }, 
      10000);
  }

  //showing this to the user
  console.log("");
  console.log("Door #" + randomDoor2 + " does not have the prize.");

  //having the computer make a desicion
  if (random(0,100) < chance) {
    decide = "swap doors.";
    while ((randomDoor3 == randomDoor2) || (randomDoor3 ==  randomDoor)) {
      randomDoor3 = Math.round(random(1,3));
    }
  } else {
    decide = "keep the current door.";
  }

  //letting the user know of the computer's desicion
  console.log("");
  console.log("The AI chose to " + decide);

  // figuring out if the AI won
  if (randomDoor3 == prizeDoor || randomDoor == prizeDoor) {

    console.log("AI won!");

    if (decide == "swap doors.") {
      chance -= 5;
    } else {
      chance += 5;
    }
  } else {

    console.log("AI lost.");

    if (decide == "swap doors.") {
      chance += 5;
    } else {
      chance -= 5;
    }
  }
}

Answer 2

编辑我让代码工作了，做了一些改动，让它像math.random一样在我这端工作，但是应该不难改回来，也是stackoverflow的新手，所以我花了一段时间来弄清楚代码片段粘贴:p。

<script type="text/javascript">

var chance; // swap | dont swap
var prizeDoor;
var randomDoor;
var randomDoor2;
var randomDoor3;
var decide;
var chance = 50;
function setup() {
  createCanvas(1000,1000);
}

function draw() {
 //setting up round

  prizeDoor = Math.floor((Math.random() * 3) + 1);
  console.log(prizeDoor+" prizeDoor");

  //choosing first door
  console.log("[1] [2] [3]");
  randomDoor = Math.floor((Math.random() * 3) + 1);
  randomDoor2 = Math.floor((Math.random() * 3) + 1);
  randomDoor3 = Math.floor((Math.random() * 3) + 1);


  //showing user the door AI picks

  if (randomDoor == 1) {
    console.log(" ^");
    console.log(" |");
  } else if (randomDoor == 2) {
    console.log("     ^");
    console.log("     |");
  } else {
    console.log("         ^");
    console.log("         |");
  }



  console.log("AI chooses door #" + randomDoor + ".");


  //revealing a door

  //getting a number that isnt the players door or the prize door
  while ((randomDoor2 == prizeDoor) || (randomDoor2 == randomDoor)) {
   randomDoor2 = Math.floor((Math.random() * 3) + 1);
  }

  //showing this to the user
  console.log("");
  console.log("Door #" + randomDoor2 + " does not have the prize.");

  //having the computer make a desicion
  if (Math.floor((Math.random() * 100) + 1) < chance) {
    decide = "swap doors.";
    while ((randomDoor3 == randomDoor2) || (randomDoor3 == randomDoor)) {
      randomDoor3 = Math.floor((Math.random() * 3) + 1);
    }
  } else {
    randomDoor3 = randomDoor;
    decide = "keep the current door.";
  }

  //letting the user know of the computer's desicion
  console.log("");
  console.log("The AI chose to " + decide);

  // figuring out if the AI won
  if (randomDoor3 == prizeDoor) {

    console.log("AI won!");

    if (decide == "swap doors.") {
      chance -= 5;
    } else {
      chance += 5;
    }
  } else {

    console.log("AI lost.");

    if (decide == "swap doors.") {
      chance += 5;
    } else {
      chance -= 5;
    }
  }
}

draw();
</script>

Answer 3

您将连续创建两个随机数prizeDoor & randomDoor，因此很难在两个连续的命中中使用Math.random生成相同的数。

在你的while循环中，你期望你的新的随机数与你之前的两个随机数匹配，因为一次点击/编译，它们可以是相同的，也可以不是，如果它们不相同，那么你的while循环将永远不会终止，这是没有用的，

比如a=1和b=2

现在期望c==a && c==b永远不会发生，因为a!=b；

在while循环中更改c不会有任何影响。所以你的逻辑是完全错误的，让我们知道你试图实现什么，然后我们可以帮助建立逻辑

​

let random = () => Math.random() * 3;
let prizeDoor = Math.round(random());
console.log('prizeDoor', prizeDoor)
let randomDoor = Math.round(random());
console.log('randomDoor', randomDoor)

​