如何从codeigniter内部的CURL响应中提取所需的数据？

Question

我尝试使用https://rapidapi.com/lambda/api/face-recognition-and-face-detection/details的接口，得到的响应如下

    {
"visualization": [
{
"image": "http://api.lambdal.com/nsuploads/6ed566063d/rawImages/09Feb21_153425_102613.jpg",
"entryid": "Face931873b7a3"
},

{
"image": "http://api.lambdal.com/nsuploads/6ed566063d/rawImages/09Feb21_152054_338756.jpg",
"entryid": "Face2e3921dee2"
}
],
"string": "<Album(6ed566063d) len: 4>",
    "name": "6ed566063d",
    "entries": [
    "Face931873b7a3",
    "Face2e3921dee2"
    ],
    "model": "<Model len: 4>",
        "size": 4
        }

这是我的控制器：

public function viewAlbum($idx=null)
    {
        $id = $idx;
        if($idx == null || $idx == ''){
            redirect('Photo');
        } else {
            $dataAlbum = $this->admin->data_album($id);
            if($dataAlbum->num_rows() != 0){
                    $namaAlbum = $dataAlbum->row()->nama_album;
                    $albumKey = $dataAlbum->row()->kode_album;
                    $data['title'] = "Dashboard | FaceVoting Versi 1.0";
                    $data['getViewAlbum']= json_decode($this->cekAlbum($namaAlbum,$albumKey),true);
                    $view ='v_detailalbum';
                    $this->_template($data,$view);
            }else{
                redirect('Album');
            }
        }
    }

    private function cekAlbum($namaAlbum,$albumKey)
    {
        $curl = curl_init();

        curl_setopt_array($curl, [
            CURLOPT_URL => "https://lambda-face-recognition.p.rapidapi.com/album?album=".$namaAlbum."&albumkey=".$albumKey,
            CURLOPT_RETURNTRANSFER => true,
            CURLOPT_FOLLOWLOCATION => true,
            CURLOPT_ENCODING => "",
            CURLOPT_MAXREDIRS => 10,
            CURLOPT_TIMEOUT => 30,
            CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
            CURLOPT_CUSTOMREQUEST => "GET",
            CURLOPT_HTTPHEADER => [
                "x-rapidapi-host: lambda-face-recognition.p.rapidapi.com",
                "x-rapidapi-key: 932571abf0msh45cf0f3cef74aacp19e151jsn33e9949a1974"
            ],
        ]);

        $response = curl_exec($curl);
        $err = curl_error($curl);

        curl_close($curl);

        if ($err) {
//          echo "cURL Error #:" . $err;
            return null;
        } else {
            return $response;
        }
    }

我已经在我的视图上尝试过了：

<?= $getViewAlbum->visualization[0][0]; ?>

我想要的是:我想在页面视图中显示数据可视化->图像作为图像源、名称和模型->大小

Answer 1

你的响应是JSON，你只需要像这样使用json_decode()

$result = json_decode($response);
$result->visualization[0]->image;

或者获取数组结果而不是对象

$result = json_decode($response, true);
$result['visualization'][0]['image'];