jsonpickle:如何正确编码和显示重复的对象而不是引用？

Question

我正在尝试让jsonpickle转储数据，以便显式显示重复项，而不是使用引用。我尝试使用make_refs=False编码，这阻止了它使用py/id引用，但仍然没有显式地显示重复项。这是我遇到的一个简单的例子：

from typing import List
import jsonpickle

class Thing:
    def __init__(self, name: str = None, desc: str = None):
        self.name = name
        self.desc = desc

class BiggerThing:
    def __init__(self, name: str = None, things: List[Thing] = None):
        self.name = name
        self.things = things if things else []

thing1 = Thing("First", "the first thing")
thing2 = Thing("Seoond", "the second thing")
thing3 = Thing("Third", "the third thing")

main_thing = BiggerThing("The main thing", [thing1, thing2, thing3, thing1])

如果我随后使用jsonpickle.encode(main_thing, make_refs=False, indent=2)进行编码，我得到的结果如下所示：

{
  "py/object": "__main__.BiggerThing",
  "name": "The main thing",
  "things": [
    {
      "py/object": "__main__.Thing",
      "name": "First",
      "desc": "the first thing"
    },
    {
      "py/object": "__main__.Thing",
      "name": "Seoond",
      "desc": "the second thing"
    },
    {
      "py/object": "__main__.Thing",
      "name": "Third",
      "desc": "the third thing"
    },
    "<__main__.Thing object at 0x000001FFACA08408>"
  ]
}

我以前没有使用过jsonpickle，所以我想我遗漏了一些简单的东西。我如何获取它，以便jsonpickle以这种方式对其进行编码：

{
  "py/object": "__main__.BiggerThing",
  "name": "The main thing",
  "things": [
    {
      "py/object": "__main__.Thing",
      "name": "First",
      "desc": "the first thing"
    },
    {
      "py/object": "__main__.Thing",
      "name": "Seoond",
      "desc": "the second thing"
    },
    {
      "py/object": "__main__.Thing",
      "name": "Third",
      "desc": "the third thing"
    },
    {
      "py/object": "__main__.Thing",
      "name": "First",
      "desc": "the first thing"
    }
  ]
}

如果有另一个模块可以做得更好，我也很乐意这样做。谢谢！

Answer 1

试试main_thing = BiggerThing("The main thing", [thing1, thing2, thing3, thing1.copy()])