我是一个刮刮和硒的新手。我想要抓取的页面使用按钮上的js脚本转到下一页。我在SO上找到了部分代码(Click a Button in Scrapy),但我似乎无法让它工作。
from selenium import webdriver
import scrapy
class chSpider(scrapy.Spider):
name = 'spidypy'
allowed_domains = ['117.145.177.252']
start_urls = ['http://117.145.177.252/login.do?method=enterPdamccx']
def __init__(self):
self.driver = webdriver.Firefox()
def parse(self,response):
self.driver.get('http://117.145.177.252/login.do?method=enterPdamccx')
while True:
try:
next = self.driver.find_element_by_xpath('/html/body/form/div[3]/div/div/a')
url = 'http://117.145.177.252/login.do?method=enterPdamccx'
yield Request(url,callback=self.parse2)
next.click()
except:
break
self.driver.close()
def parse2(self,response):
print('you are here!')我多次收到以下错误消息:
selenium.common.exceptions.WebDriverException: Message: connection refused发布于 2019-03-25 08:29:01
它有一个onclick,所以你可以这样做:
driver.execute_script('doMccx()')https://stackoverflow.com/questions/55326453
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