Python ()函数在使用.strip (BeautifulSoup)时给出变量错误

Question

这段代码从amazon抓取产品名称。我想去掉这个变量，它包含HTML的空格，

span = soup.find("span", id="productTitle")
print(span.strip())

但它给了我这个错误；

Traceback (most recent call last):
  File "C:/Users/avensis/Desktop/Projects/AmazonScraper/Scraper.py", line 17, in <module>
    print(span.strip())
TypeError: 'NoneType' object is not callable

我不明白为什么会这样。有人能解释一下吗？下面是我的完整代码：

from bs4 import BeautifulSoup
import requests
import html5lib

url = 'https://www.amazon.co.uk/Pingu-PING2573-Mug/dp/B0764468MD/ref=sr_1_11?dchild=1&keywords=pingu&qid=1595849018' \
      '&sr=8-11 '
headers = {
    "User-Agent": 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) '
                  'Chrome/84.0.4147.89 Safari/537.36'}
page = requests.get(url, headers=headers)
soup = BeautifulSoup(page.content, 'html5lib')
span = soup.find("span", id="productTitle")
print(span.strip())

Answer 1

我猜这就是你想要做的：

from bs4 import BeautifulSoup
import requests
import html5lib
import random

url = 'https://www.amazon.co.uk/Pingu-PING2573-Mug/dp/B0764468MD/ref=sr_1_11?dchild=1&keywords=pingu&qid=1595849018' \
      '&sr=8-11 '
headers = {
    "User-Agent": 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) '
                  'Chrome/84.0.4147.89 Safari/537.36'}
page = requests.get(url, headers=headers)
soup = BeautifulSoup(page.content, 'html5lib')


span = soup.find("span", id="productTitle")

print(span.get_text(strip=True))

打印：

Pingu - Mug | 300 ml | Ceramic | Gift Box | 11 x 8.5 x 8.5 cm

如果这就是你要找的，那就是你错过的.get_text(strip=True)

Answer 2

使用.get_text()方法：

span.get_text().replace("\n", "")

'Pingu - Mug | 300 ml | Ceramic | Gift Box | 11 x 8.5 x 8.5 cm'