打印函数打印True，但也打印false

Question

我对这段代码的问题是，我想让它打印当前的进攻:球员，也打印当前的防守者: Cpu。

代码如下：

import random

Player = False
Cpu = False
user = input("Please enter [H]eads or [T]ails: ")

def flip_coin(Player, Cpu, user):
    # Flips coin to determine who has the ball first. 
    COIN = ["H", "T"]
    coin = random.choice(COIN)
    print("Coin is on: " + str(coin))
    
    if coin == user:
        Player = True
        return "Player"
    else:
        Cpu = True
        return "Cpu"

print("Current Offence: " + str(flip_coin(Player, Cpu, user)))
print("Current Deffence: " + str(flip_coin(Player, Cpu, user)))

输出：

Please enter [H]eads or [T]ails: H
Coin is on: H
Current Offence: Player
Coin is on: H
Current Deffence: Player

预期输出：

Please enter [H]eads or [T]ails: H
Coin is on: H
Current Offence: Player
Current Deffence: Cpu

我怎么才能到达当前的进攻在玩家身上，但当前的差异在Cpu上，而不是在玩家身上的地方？

Answer 1

您只需要一个bool (或int)来保存所有信息：

import random

players = ["Cpu", "Player"]

def flip_coin(coin):
    return random.choice("HT") == coin

user = input("Please enter [H]eads or [T]ails: ")        
player = flip_coin(user)
print(f"Current Offence: {players[player]}")     # Note: True == 1
print(f"Current Defence: {players[not player]}") # and: False == 0