在R包'timetk‘中,如何理解函数'diff_vec’中的参数'difference‘?
library(timetk)
1:10 %>% diff_vec(lag=1)
#result: [1] NA 1 1 1 1 1 1 1 1 1我试着改变“差异”的值,但不能理解结果
#what's the usage of parameter 'difference'
1:10 %>% diff_vec(lag=1,difference = 1)
#result: [1] NA 1 1 1 1 1 1 1 1 1
1:10 %>% diff_vec(lag=1,difference = 2)
#result: [1] NA NA 0 0 0 0 0 0 0 0
1:10 %>% diff_vec(lag=1,difference = 3)
#result: [1] NA NA NA 0 0 0 0 0 0 0发布于 2021-11-22 07:14:58
使用(1:10)^2可能更容易理解。参数difference多次执行连续值之间的差(微分)。
(1:10)^2 %>% diff_vec(lag=1,difference = 1)
[1] NA 3 5 7 9 11 13 15 17 19For difference = 2表示执行两次difference = 1。
(1:10)^2 %>% diff_vec(lag=1,difference = 1) %>% diff_vec(lag=1,difference = 1)
[1] NA NA 2 2 2 2 2 2 2 2
(1:10)^2 %>% diff_vec(lag=1,difference = 2)
[1] NA NA 2 2 2 2 2 2 2 2以同样的方式,difference = 3表示执行difference = 1三次。
(1:10)^2 %>% diff_vec(lag=1,difference = 1) %>% diff_vec(lag=1,difference = 1) %>% diff_vec(lag=1,difference = 1)
[1] NA NA NA 0 0 0 0 0 0 0
(1:10)^2 %>% diff_vec(lag=1,difference = 3)
[1] NA NA NA 0 0 0 0 0 0 0https://stackoverflow.com/questions/70062024
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