输出绑定到数组的符号(C++)

Question

本质上，我需要它为每一辆售出的汽车显示一个星号，然而，无论在第一个for循环中输入什么，它只输出一次符号，我做错了什么？提前谢谢。

#include 
#include 
using namespace std;

const int NUM_EMPLOYEES = 3;

int main()
{
    int carsSold[NUM_EMPLOYEES];
    int i;
    int totalSales = 0;
    char symbol = '*';

    cout << "Welcome to the sales report program!\n";
    cout << "\nThis program will produce a monthly sales report for the amount of cars sold.\n";

    for (i = 0; i < NUM_EMPLOYEES; i++)
    {
        cout << "Enter the cars sold by employee " << i + 1 << ": ";
        cin >> carsSold[i];

        totalSales += carsSold[i];
    }

    cout << "\nMonthly Sales Sheet";
    cout << "\n(each * = 1 car)\n";

    for (i = 0; i < carsSold[i]; i++)
    {
        cout << "\nEmployee " << i + 1 << ": " << symbol << endl;
    }

    cout << "\nTotal cars sold for the month: " << totalSales;



    return 0;
}

下面是输出：

欢迎来到销售报告节目！

该程序将生成汽车销量的月度销售报告。

输入员工1: 3售出的汽车

输入员工2: 2售出的汽车

输入员工3: 4售出的汽车

每月销售表(每个*=1辆车)

员工1：*

员工2：*

员工3：*

当月汽车总销量:9辆

Answer 1

使用我上面给你的提示：

#include 
#include 
using namespace std;

#define NUM_EMPLOYEES 3

...

cout << "\nMonthly Sales Sheet";
cout << "\n(each * = 1 car)\n";
for (i = 0; i < NUM_EMPLOYEES; i++)
{
    auto bar = new string(carsSold[i], symbol);
    cout << "\nEmployee " << i + 1 << ": " << *bar << endl;
}
cout << "\nTotal cars sold for the month: " << totalSales << "\n";

...

这将导致以下输出：

This program will produce a monthly sales report for the amount of cars sold.
Enter the cars sold by employee 1: 3
Enter the cars sold by employee 2: 2
Enter the cars sold by employee 3: 4

Monthly Sales Sheet
(each * = 1 car)

Employee 1: ***

Employee 2: **

Employee 3: ****