Python雨量计，更正误报

Question

我在Pi Zero上运行了以下脚本，并附加了一个倾倒桶雨量计。正如您所看到的，它会统计提示的数量，并每30分钟记录一次sql。不过，我还是有一些误报。大约每30分钟1到2次。每一天，即使是最干燥的日子。我怎样才能避免它们呢？我在想这样的事情：

if rainTick <= 2:
     rainTick = 0

但我不想让它重置一整天，只重置最后30分钟。它应该只会在午夜完全重置。

import time
import datetime
import RPi.GPIO as GPIO
import mysql.connector

rainTick = 0
Input_Sig = 6
starttime = time.time()
last_day = datetime.datetime.now().day
lastrainevent = datetime.datetime.now()

GPIO.setmode(GPIO.BCM)
GPIO.setup(Input_Sig, GPIO.IN, pull_up_down=GPIO.PUD_UP)
GPIO.add_event_detect(Input_Sig, GPIO.FALLING,  bouncetime=5)

def raintrig(self):
    global rainTick
    rainTick += 1
 
mydb = mysql.connector.connect(
    host='localhost',
    user='pi',
    passwd='************',
    database='weatherDB'
)
mycursor = mydb.cursor()

def write2DB(values):
    sqlText = '''INSERT INTO rainfall(rain) VALUES({:.2f})'''.format(values)
    #print( values, 'mm')
    mycursor.execute(sqlText)
    mydb.commit()

GPIO.add_event_callback(Input_Sig, raintrig)

while True:
 
    rainFall = rainTick * 0.2794
    day = datetime.datetime.now().day
    if day != last_day:
        last_day = day
        rainTick = 0
    print(rainFall, 'mm')
    write2DB(rainFall)
    time.sleep(1800.0 - ((time.time() - starttime) % 60.0))

Answer 1

好吧，我想我可能已经解决了。至少是一个非常基本的方法。

import time
import datetime
import RPi.GPIO as GPIO
import mysql.connector

rainTick = 0
lastTick = 0
inputPin = 6
startTime = time.time()
lastDay = datetime.datetime.now().day

GPIO.setmode(GPIO.BCM)
GPIO.setup(inputPin, GPIO.IN, pull_up_down=GPIO.PUD_UP)
GPIO.add_event_detect(inputPin, GPIO.FALLING,  bouncetime=5)

def rainTrig(self):
    global rainTick
    global lastTick
    rainTick += 1
    lastTick += 1
    
mydb = mysql.connector.connect(
    host='localhost',
    user='pi',
    passwd='Snabela1',
    database='weatherDB'
)
mycursor = mydb.cursor()

def write2DB(values):
    sqlText = '''INSERT INTO rainfall(rain) VALUES({:.2f})'''.format(values)
    mycursor.execute(sqlText)
    mydb.commit()

GPIO.add_event_callback(inputPin, rainTrig)

while True:
 
    if lastTick <= 2:
        rainTick -= lastTick   
    rainFall = rainTick * 0.2794
    day = datetime.datetime.now().day
    if day != lastDay:
        lastDay = day
        rainTick = 0
    lastTick = 0
    #print(rainFall, 'mm')
    write2DB(rainFall)
    time.sleep(1800.0 - ((time.time() - startTime) % 60.0))

我设置了一个新变量，每次重置一次，如果它等于1或2，它会从总数中减去vlue。