在PHP中将多维数组插入到多维json中

Question

我想用我在数据库中的数据把一些数据插入到json data中的sub中。

下面是我的代码：

$sql = "SELECT * FROM pharma_data";
$result = mysqli_query($conn, $sql);


$data = array();
while ($row = mysqli_fetch_assoc($result)){
    $row_array['id'] = $row['phar_id'];
    $row_array['name'] = $row['name'];
    $row_array['batch'] = $row['batch_no'];
    $row_array['category'] = $row['category'];
    $row_array['measurement'] = $row['measurement'];
    $row_array['stock'] = $row['stock'];
    $row_array['price'] = $row['price'];
    $row_array['date'] = $row['date_added'];
    $row_array['expiration'] = $row['expiration_date'];
    $row_array['type'] = $row['medicin_type'];
    $row_array['supplier'] = $row['supplier'];
    array_push($data,$row_array);
}

$convert = json_encode($data);
echo $convert;

但是我的代码的输出是：

[{"id":"8","name":"Test Product Name Pharmacy","batch":"Test Product Name Pharmacy","category":"Test Category Pharmacy","measurement":"1mg","stock":"2","price":"15","date":"February 18, 2021, 11:36 am","expiration":"2021-02-18","type":"Test Medicine Type Pharmacy","supplier":"Nicole Gonzaga"},{"id":"9","name":"Alaxan","batch":"Test user medicine Supplies","category":"Test Category Pharmacy","measurement":"1mg","stock":"66","price":"63.43","date":"February 28, 2021, 4:45 pm","expiration":"2021-02-28","type":"Test Medicine Type Pharmacy","supplier":"Nicole Gonzaga"},{"id":"10","name":"Medicol","batch":"987","category":"Test Category Pharmacy","measurement":"1mg","stock":"15","price":"123.23","date":"February 28, 2021, 5:42 pm","expiration":"2021-02-28","type":"Test Medicine Type Pharmacy","supplier":"Nicole Gonzaga"},{"id":"11","name":"test","batch":"test","category":"Test Category Pharmacy","measurement":"213","stock":"32","price":"123.78","date":"February 28, 2021, 6:43 pm","expiration":"2021-02-28","type":"Test Medicine Type Pharmacy","supplier":"Nicole Gonzaga"}]

想要这样的输出：

{
  "total": 800,
  "totalNotFiltered": 800,
  "rows": [
    {
      "id": 0,
      "name": "Item 0",
      "price": "$0"
    },
    {
      "id": 1,
      "name": "Item 1",
      "price": "$1"
    }
  ]
}

在此处输入图像描述

Answer 1

你需要过滤掉

在将其发送到响应之前，这意味着我们需要一个函数

要筛选

元素，我们可以使用以下命令过滤数组中的所有元素

..。The The The

和

列似乎给出了

因此，

..。尝试下面的代码：

function myFilter($a) {
    $row['id'] = $a['id'];
    $row['name'] = $a['name'];
    $row['price'] = $a['price'];
   return $row;
};

$filterData = array(
    'total' => count($data),
    'totalNotFiltered' => count($data),
    'rows' => array_map("myFilter", $data)
);

$convert = json_encode($filterData);
echo $convert;

演示代码如下：

https://ideone.com/pZCUbG

Answer 2

需要对返回的数据进行转换。类似于：

$data = array();
while ($row = mysqli_fetch_assoc($result)){
    $row_array['id'] = $row['phar_id'];
    $row_array['name'] = $row['name'];
    // $row_array['batch'] = $row['batch_no'];
    // $row_array['category'] = $row['category'];
    // $row_array['measurement'] = $row['measurement'];
    // $row_array['stock'] = $row['stock'];
    $row_array['price'] = $row['price'];
    // $row_array['date'] = $row['date_added'];
    // $row_array['expiration'] = $row['expiration_date'];
    // $row_array['type'] = $row['medicin_type'];
    // $row_array['supplier'] = $row['supplier'];
    $data[] = $row_array; // Same as array_push($data,$row_array);
}

$final_data = array(
    'total' => count($data),
    'totalNotFiltered' => '',
    'rows' => $data
);

$convert = json_encode($final_data);
echo $convert;

注释掉了在此上下文中不需要的数据(也许您需要在其他地方使用它，但不确定。如果是这样，只需取消注释即可)

不确定

因为我不知道你是怎么计算的。也许你可以使用它，这给了你一个可以使用的想法。