相同的方程在Matlab和Numpy中给出不同的值？

Question

我正在尝试将一个函数从Matlab转换为Python。Matlab函数为：

function [f,df_dr1,df_dr2,g,dg_dr1,dg_dr2] = f_eval_2eq(r1,r2,r3,z1,z2,z3,n1,n2,n3)

f      = (r1)./sqrt(r1.^2 + z1.^2)...
- (n2/n1)*(r2-r1)./sqrt((r2-r1).^2 + z2.^2);

df_dr1 = 1./sqrt(r1.^2 + z1.^2)...
- r1.^2./(r1.^2 + z1.^2).^(3/2)...
+ (n2/n1)./sqrt(z2.^2 + (r1-r2).^2)...
- (n2/n1).*(r1-r2).*(2*r1-2*r2)./(2*((r1-r2).^2 + z2.^2).^(3/2));

df_dr2 = (n2/n1).*(r1-r2).*(2*r1-2*r2)./(2*((r1-r2).^2 + z2.^2).^(3/2))...
- (n2/n1)./sqrt(z2.^2 + (r1-r2).^2);


g      = (r2-r1)./sqrt((r2-r1).^2 + z2.^2)...
- (n3/n2)*(r3-r2)./sqrt((r3-r2).^2 + z3.^2);

dg_dr1 = (r1-r2).*(2*r1-2*r2)./(2*((r1-r2).^2 + z2.^2).^(3/2))...
- 1./sqrt(z2.^2 + (r1-r2).^2);

dg_dr2 = 1./sqrt((r1-r2).^2 + z2.^2)...
+ (n3/n2)./sqrt(z3.^2 + (r2-r3).^2)...
- (r1-r2).*(2*r1-2*r2)./(2*((r1-r2).^2 + z2.^2).^(3/2))...
- (n3/n2).*(r2-r3).*(2*r2-2*r3)./(2*((r2-r3).^2 + z3.^2).^(3/2));

end

%test code
K>> a=[1,2,3];b=a+1;c=b+1;d=a;e=b;f=c;g=1;h=2;i=3;
K>> [f,df_dr1,df_dr2,g,dg_dr1,dg_dr2] = f_eval_2eq(a,b,c,d,e,f,g,h,i)

我编写的Python函数是：

def f_eval_2eq(r1,r2,r3,z1,z2,z3,n1,n2,n3):
    #evaluate gradients
    #n_ are scalars
    f = (r1)/np.sqrt(r1**2 + z1**2) \
        - (n2/n1)*(r2-r1)/np.sqrt((r2-r1)**2 + z2**2);

    df_dr1 = 1/np.sqrt(r1**2 + z1**2) \
             - r1**2/((r1**2 + z1**2)**(3/2)) \
             + (n2/n1)/np.sqrt(z2**2 + (r1-r2)**2) \
             - (n2/n1)*(r1-r2)*(2*r1-2*r2)/(2*((r1-r2)**2 + z2**2)**(3/2));

    df_dr2 = (n2/n1)*(r1-r2)*(2*r1-2*r2)/(2*((r1-r2)**2 + z2**2)**(3/2)) \
             - (n2/n1)/np.sqrt(z2**2 + (r1-r2)**2);


    g      = (r2-r1)/np.sqrt((r2-r1)**2 + z2**2) \
             - (n3/n2)*(r3-r2)/np.sqrt((r3-r2)**2 + z3**2);

    dg_dr1 = (r1-r2)*(2*r1-2*r2)/(2*((r1-r2)**2 + z2**2)**(3/2)) \
             - 1/np.sqrt(z2**2 + (r1-r2)**2);

    dg_dr2 = 1/np.sqrt((r1-r2)**2 + z2**2) \
             + (n3/n2)/np.sqrt(z3**2 + (r2-r3)**2) \
             - (r1-r2)*(2*r1-2*r2)/(2*((r1-r2)**2 + z2**2)**(3/2)) \
             - (n3/n2)*(r2-r3)*(2*r2-2*r3)/(2*((r2-r3)**2 + z3**2)**(3/2));

    return (f,df_dr1,df_dr2,g,dg_dr1,dg_dr2)

#test code
A=np.array([1,2,3])
B=A+1
C=B+1
D=A
E=B
F=C
G=1
H=2
I=3
[f,df_dr1,df_dr2,g,dg_dr1,dg_dr2] =f_eval_2eq(A,B,C,D,E,F,G,H,I)
print ('f= '+str(f) +'\n'+'df_dr1= '+str(df_dr1) +'\n' +'df_dr2='+str(df_dr2) +'\n'+'g= '+str(g) +'\n'+'dg_dr1= '+str(dg_dr1) +'\n'+'dg_dr2= '+str(dg_dr2) +'\n')

F的输出在这两个文件中是相同的，但所有其他值都不同，我不知道为什么？

任何帮助都是非常感谢的。