为vertx项目生成OpenAPI规范

Question

我想为我的vertx项目生成一个OpenAPI规范。所以我有一个简单的vertx服务器，如下所示，它只返回一个json对象：

package server;

import io.vertx.core.AbstractVerticle;
import io.vertx.core.http.HttpServer;
import io.vertx.core.http.HttpServerRequest;
import io.vertx.core.http.HttpServerResponse;
import io.vertx.core.json.JsonArray;
import io.vertx.core.json.JsonObject;
import io.vertx.ext.web.Router;
import io.vertx.ext.web.RoutingContext;
import io.vertx.ext.web.handler.BodyHandler;

public class Server extends AbstractVerticle {

  @Override
  public void start() throws Exception {
    HttpServer server = vertx.createHttpServer();
    Router router = Router.router(vertx);
    router.route("/v0.2.2/*").handler(this::responseSetUp);
    router.get("/v0.2.2/location").handler(this::getLocation);
    server.requestHandler(router::accept).listen(8004);
  }

  public void responseSetUp(RoutingContext context) {
    HttpServerResponse response = context.response();
    response.putHeader("Access-Control-Allow-Origin", "*")
        .putHeader("Access-Control-Allow-Methods", "GET, POST, PUT , DELETE, OPTIONS")
        .putHeader("Access-Control-Allow-Headers", "Content-Type,cache-control, x-requested-with")
        .putHeader("Access-Control-Max-Age", "86400");
    context.next();
  }

  public void getLocation(RoutingContext context) {
    JsonObject location = new JsonObject();
    location.put("city", "Bangalore");
    location.put("country", "India");
    location.put("pin", 560095);
    HttpServerResponse response = context.response();
    response.putHeader("content-type", "application/json");
    response.setChunked(true);
    response.write(location.toString());
    response.end();
  }
}

我只想为此路由生成一个OpenAPI规范。我刚接触Swagger，到目前为止，在谷歌上我可以看到RestEasy，Mule，Jersey1，Jersey2，Spring的教程，但不能看到vertx的教程。

有没有人能帮我个忙，或者有什么建议？

抱歉，如果这个问题太天真了。