我在powershell中有一个字符串,它包含以下数据,
$job = "diagnosticCode":223412290,
"severity":"Error",
"component":"JobManager_User",
"source":"User",
"errorId":"VertexFailedFast",
"message":"Vertex failed with a fail-fast error",
"description":"Vertex failure triggered quick job abort".
"resolution":"",
"helpLink":""在这里,我想捕获“消息”,并在捕获情况下将其提供给exception,尝试使用$job3.ToSTring(),但无法解决。有什么需要帮忙的吗?
https://stackoverflow.com/questions/44426782
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