3DTouch UIPreviewAction: performseguewithidentifier不起作用

Question

我在我的iOS Swift应用程序中实现了一些peek UIPreviewActions。但是，这些操作将执行segue事务，而这些事务将被忽略。我如何才能做到这一点？

还有一个类似的问题，但在Objective-C中：UIPreviewAction to Mail From Peek

override func previewActionItems() -> [UIPreviewActionItem] {
    let performSegueAction = UIPreviewAction(title: "Go To View", style: .Default) { (action, viewController) -> Void in
    self.performSegueWithIdentifier("segueID", sender: self)
    }
    return [performSegueAction]
}

Answer 1

很抱歉回复晚了，但我自己最近遇到了这个问题，所以把答案贴出来，以防别人觉得有用……

在调用UIPreviewAction中的处理程序时，视图控制器已经从层次结构中删除，因此执行segues没有任何效果。相反，你应该这样做：

class PreviewViewController: UIViewController {

var performAction: (() -> Void)?

override func previewActionItems() -> [UIPreviewActionItem] {
    let performSegueAction = UIPreviewAction(title: "Go To View", style: .Default) { (action, viewController) -> Void in
        self.performAction?()
    }
    return [performSegueAction]
}

在父控制器(从其中启动预览)中：

class ParentViewController: UIViewController {

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    if let vc = segue.destination as? PreviewViewController {
        vc.handleAction = {
            self.performSegueWithIdentifier("segueID", sender: self)
        }
    }
    inject(toController: segue.destination)
}