天气应用编程接口的JSon日期解析

Question

我一直在分析我的天气数据我可以成功地提取描述，最低和最高温度，但日期是未知的格式如何处理日期将其转换为可读格式

  "list":[  
  {  
     "dt":1497852000,
     "temp":{  
        "day":301.14,
        "min":294.81,
        "max":301.14,
        "night":294.81,
        "eve":301.14,
        "morn":301.14
     },
"pressure":990.68,
     "humidity":88,
     "weather":[  
        {  
           "id":501,
           "main":"Rain",
           "description":"moderate rain",
           "icon":"10d"
        }

我的代码：

 public static void JSONParsing(String forecastJsonStr) throws JSONException {
    double MinTemp;
    double MaxTemp;
    String Date,description;
    JSONObject forecastDate = new JSONObject(forecastJsonStr);
    JSONArray ForecastData = forecastDate.getJSONArray("list");
    for(int i =0 ; i< ForecastData.length();i++){
        JSONObject weather = ForecastData.getJSONObject(i);
        JSONObject Data = weather.getJSONObject("temp");
        JSONObject Description = weather.getJSONArray("weather").getJSONObject(0);
         description = Description.getString("description");
        MinTemp = Data.getDouble("min");
        MaxTemp = Data.getDouble("max");


    }
}

Answer 1

您的日期是seconds格式的long类型，因此请尽可能长时间地获取dt，然后将其与1000相乘，以将其转换为miliseconds，使用Date和SimpleDateFormat

1.)获取您的日期作为long

2.)将其传递给Date类构造函数，同时将其与1000相乘，以将秒转换为毫秒

3.)创建并应用SimpleDateFormat来获取日期

e.g

    String s1 ="{\"dt\":1497852000}";
    JSONObject jsonObject2 = new JSONObject(s1);

    java.util.Date date = new java.util.Date(jsonObject2.getLong("dt")*1000);
    SimpleDateFormat date_format = new SimpleDateFormat("dd/MM/yy");
    String dateText = date_format.format(date);
    System.out.println(dateText); 

输出：

19/06/17

注意:由于您的JSONResponse不完整，所以我只添加了一个简单的案例来演示您的问题

Answer 2

你可以像这样格式化，

    try {
        JSONObject responseObject = new JSONObject(response);


        JSONArray listJsonArray = responseObject.optJSONArray("list");

        if (listJsonArray == null || listJsonArray.length() == 0) {
            return;
        }

        for (int i = 0; i < listJsonArray.length(); i++) {
            JSONObject eachDayJson = listJsonArray.optJSONObject(i);

            if (eachDayJson == null) {
                continue;
            }

            long dateInSeconds = eachDayJson.optLong("dt"); // Get date as seconds

            SimpleDateFormat format = new SimpleDateFormat("dd-MMM-yyyy HH:mm");

            String readableDate = format.format(new Date(dateInSeconds * 1000)); // convert that in milliseconds

        }
    } catch (JSONException e) {
        e.printStackTrace();
    }