MySql引发运行此sql的ProgrammingError
SELECT parents.uuid AS parents_uuid, children.uuid AS children_uuid,
children.parent_uuid AS children_parent_uuid,
count(*) OVER (PARTITION BY parents.uuid) AS children_count
FROM parents, children
WHERE children.parent_uuid = parents.uuid ORDER BY children_count DESC错误:
sqlalchemy.exc.ProgrammingError: (_mysql_exceptions.ProgrammingError) (1064, "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(PARTITION BY parents.uuid)' at line 1") [SQL: 'SELECT parents.uuid AS parents_uuid, children.uuid AS children_uuid, children.parent_uuid AS children_parent_uuid, count(*) OVER (PARTITION BY parents.uuid)']使用模式,其中Parent可以有多个children,而Child只有一个parent
Base = declarative_base()
class Parent(Base):
__tablename__ = 'parents'
uuid = Column(String(64), primary_key=True, unique=True)
def __init__(self):
self.uuid = uuid.uuid4()
class Child(Base):
__tablename__ = 'children'
uuid = Column(String(64), primary_key=True, unique=True)
parent_uuid = Column(String(64), ForeignKey('parents.uuid'))
def __init__(self, parent_uuid=None):
self.uuid = uuid.uuid4()
self.parent_uuid = parent_uuid发布于 2017-01-16 00:48:23
MySQL中不支持窗口函数。要解决此问题,请使用相关子查询来获取计数。
SELECT
p.uuid AS parents_uuid,
c.uuid AS children_uuid,
c.parent_uuid AS children_parent_uuid,
(SELECT COUNT(*) FROM children WHERE parent_uuid = p.uuid) AS children_count
FROM parents p
JOIN children c ON c.parent_uuid = p.uuid
ORDER BY children_count DESC或者使用派生表获取计数并将其join到现有查询。
SELECT
p.uuid AS parents_uuid,
c.uuid AS children_uuid,
c.parent_uuid AS children_parent_uuid,
counts.children_count
FROM parents p
JOIN (SELECT parent_uuid,COUNT(*) as children_count
FROM children
GROUP BY parent_uuid) counts ON counts.parent_uuid = p.uuid
JOIN children c ON c.parent_uuid = p.uuid
ORDER BY counts.children_count DESC发布于 2021-06-12 00:03:18
从MySQL 8.0 https://dev.mysql.com/doc/refman/8.0/en/window-functions-usage.html开始支持窗口函数
https://stackoverflow.com/questions/41663346
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