我有n次多项式系统,只是我想学习在先前确定的区间.But之间的根的个数,我不想找根,我需要根的个数,我需要写python代码。例如: x^8+2x^6+5x^4+x^2+45x+1=0我们在3-5之间有多少根?emphasize=I不想找根,我只想知道我有多少根。
发布于 2016-07-28 19:01:27
您可以使用numpy实现这一点
import numpy as np
coeff = [1,0,2,0,5,0,1,45,1] #for the polynomial x^8+2x^6+5x^4+x^2+45x+1=0
np.roots(coeff)
# array([ 1.37234708+0.91495949j, 1.37234708-0.91495949j,
# 0.43013459+1.75225934j, 0.43013459-1.75225934j,
# -1.06175643+1.53395567j, -1.06175643-1.53395567j,
# -1.45921726+0.j , -0.02223323+0.j ])因此,正如您所看到的,这一个没有实际的根。
编辑:如果您希望在不显式查找根的情况下查找某个间隔之间的根数,则可以使用sturm's theorem。使用渐近,
from sympy import Sturm,Symbol
from sympy.abc import x
sturm_seq = sturm(x**6-3*x**5+2*x**4)
limits = [2,4]; x = Symbol('x')
values_at_start = [polynomial.subs(x,limits[0]).evalf() for polynomial in sturm_seq]
values_at_end = [polynomial.subs(x,limits[1]).evalf() for polynomial in sturm_seq]
import itertools
# Count number of sign changes in values_at_start
count_start = len(list(itertools.groupby(values_at_start, lambda values_at_start: values_at_start > 0)))
count_end = len(list(itertools.groupby(values_at_end, lambda values_at_end: values_at_end > 0)))
ans = count_start - count_end
print ans # ans = 1https://stackoverflow.com/questions/38628952
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