我的目标是使用reactive streams和Project Reactor遍历目录图并记录它们的所有名称。
因为文件系统是远程的,所以对它的调用是阻塞的。因此,我希望将阻塞调用的执行与非阻塞异步代码的其余部分分开。我使用的是这个建议:http://projectreactor.io/docs/core/release/reference/#faq.wrap-blocking。
下面是我需要遍历的结构:
/
/jupiter
/phase-1
/sub-phase-1
/sub-phase-2
/sub-phase-3
/phase-2
/phase-3
/phase-4
/earth
/phase-1
/sub-phase-1
/sub-phase-2
/sub-phase-3
/phase-2
/phase-3
/phase-4
/mars
/phase-1
/sub-phase-1
/sub-phase-2
/sub-phase-3
/phase-2
/phase-3
/phase-4这是我到目前为止想出的代码:
public class ReactorEngine {
private static Logger log = LoggerFactory.getLogger(ReactorEngine.class);
public static void main(String[] args) throws InterruptedException {
CountDownLatch latch = new CountDownLatch(1);
Server server = new Server();
Flux.fromIterable(server.getChildren("/"))
.flatMap(parent -> Mono.fromCallable(() -> server.getChildren(parent)).subscribeOn(Schedulers.elastic()))
.publishOn(Schedulers.elastic())
.doOnTerminate(latch::countDown)
.subscribe(ReactorEngine::handleResponse);
latch.await();
}
private static void handleResponse(List<String> value) {
log.info("Received: " + value);
}
}
public class Server {
public List<String> getChildren(final String path) {
// Generate some I/O
...
}
}因此,我从顶层目录开始,并异步请求向下的第一层目录(它们的子目录)。一切都很顺利,下面是输出:
15:35:05.902 [main] INFO org.playground.async.mock.Server - Requesting children of: /...
15:35:07.062 [main] DEBUG reactor.util.Loggers$LoggerFactory - Using Slf4j logging framework
15:35:07.140 [elastic-3] INFO org.playground.async.mock.Server - Requesting children of: /jupiter/...
15:35:07.140 [elastic-4] INFO org.playground.async.mock.Server - Requesting children of: /earth/...
15:35:07.140 [elastic-5] INFO org.playground.async.mock.Server - Requesting children of: /mars/...
15:35:08.140 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: [/earth/phase-1/, /earth/phase-2/, /earth/phase-3/]
15:35:08.141 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: [/jupiter/phase-1/, /jupiter/phase-2/, /jupiter/phase-3/]
15:35:08.141 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: [/mars/phase-1/, /mars/phase-2/, /mars/phase-3/]现在我的问题是,如何将作为结果返回的元素放回flux中,以便引擎将递归地调用server.getChildren(父级),直到遍历完整个目录图?
实际上递归是可行的吗,还是有一种更好的“反应式”方法来实现这一点,比如通过操作符?
谢谢!
编辑
西蒙建议的expand(Function)操作符可以很好地遍历图形。我已经将代码更改为:
public static void main(String[] args) throws InterruptedException {
CountDownLatch latch = new CountDownLatch(1);
Server server = new Server();
Flux.fromIterable(server.getChildren("/"))
.expand(p -> Flux.fromIterable(server.getChildren(p)).subscribeOn(Schedulers.elastic()))
.publishOn(Schedulers.elastic())
.doOnTerminate(latch::countDown)
.subscribe(ReactorEngine::handleResponse);
latch.await();
}但是,我失去了异步调用服务器的阻塞server.getChildren(String)方法的方式。正如您在这些日志中看到的,每个子目录都是同步获取的,每秒一次:
15:57:55.398 [main] INFO org.playground.async.mock.Server - Requesting children of: /...
15:57:56.558 [main] DEBUG reactor.util.Loggers$LoggerFactory - Using Slf4j logging framework
15:57:56.593 [main] INFO org.playground.async.mock.Server - Requesting children of: /jupiter/...
15:57:56.593 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /jupiter/
15:57:57.594 [main] INFO org.playground.async.mock.Server - Requesting children of: /earth/...
15:57:57.594 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /earth/
15:57:58.594 [main] INFO org.playground.async.mock.Server - Requesting children of: /mars/...
15:57:58.594 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /mars/
15:57:59.599 [elastic-3] INFO org.playground.async.mock.Server - Requesting children of: /jupiter/phase-1/...
15:57:59.599 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /jupiter/phase-1/
15:58:00.600 [elastic-3] INFO org.playground.async.mock.Server - Requesting children of: /jupiter/phase-2/...
15:58:00.600 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /jupiter/phase-2/
15:58:01.600 [elastic-3] INFO org.playground.async.mock.Server - Requesting children of: /jupiter/phase-3/...
15:58:01.600 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /jupiter/phase-3/
15:58:02.601 [elastic-3] INFO org.playground.async.mock.Server - Requesting children of: /jupiter/phase-4/...
15:58:02.601 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /jupiter/phase-4/
15:58:03.602 [elastic-4] INFO org.playground.async.mock.Server - Requesting children of: /earth/phase-1/...
15:58:03.603 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /earth/phase-1/
15:58:04.604 [elastic-4] INFO org.playground.async.mock.Server - Requesting children of: /earth/phase-2/...
15:58:04.604 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /earth/phase-2/
15:58:05.604 [elastic-4] INFO org.playground.async.mock.Server - Requesting children of: /earth/phase-3/...
15:58:05.604 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /earth/phase-3/
15:58:06.605 [elastic-4] INFO org.playground.async.mock.Server - Requesting children of: /earth/phase-4/...
15:58:06.605 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /earth/phase-4/
15:58:07.605 [elastic-3] INFO org.playground.async.mock.Server - Requesting children of: /mars/phase-1/...
15:58:07.605 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /mars/phase-1/
15:58:08.606 [elastic-3] INFO org.playground.async.mock.Server - Requesting children of: /mars/phase-2/...
15:58:08.606 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /mars/phase-2/
15:58:09.607 [elastic-3] INFO org.playground.async.mock.Server - Requesting children of: /mars/phase-3/...
15:58:09.607 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /mars/phase-3/
15:58:10.608 [elastic-3] INFO org.playground.async.mock.Server - Requesting children of: /mars/phase-4/...
15:58:10.608 [elastic-2] INFO org.playground.async.engine.ReactorEngine - Received: /mars/phase-4/您能否提供一个提示,说明如何将对Mono.fromCallable(() -> server.getChildren(parent)).subscribeOn(Schedulers.elastic())的调用重新纳入方案中?没有我可以调用的Flux.fromCallable(),也许这是一个很好的理由。
但是,由于我对反应式编程和Project Reactor的概念非常陌生,因此很难理解这种异步方式。
谢谢。
发布于 2017-12-18 18:01:08
这里有一个运算符:)看看expand和expandDeep
https://stackoverflow.com/questions/47847132
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