Python Hangman图形

Question

我试着在我的代码中为一个绞刑者游戏添加图形。图形没有出现，当你猜一个字母时，它会自动告诉你游戏结束了。我不确定哪里出了问题，因为我对python和编码非常陌生。

import random

Graphics=['''
------------
|         |''','''


------------
|         |         
|          O''','''


------------
|         | 
|          O 
|         / |''','''

------------
|         | 
|          O 
|         / | 
|          | ''','''


------------
|         |
|          O 
|         / |
|          |
|         / | 
|
|            ''']


start = str(input("Welcome to Hangman!"))
failures = 0
allowed = 6
guesses_left = 6
guessed = str()
wordlist = ['kittens' , 'keen', 'right', 'square', 'baseball','soccer', 'square','house', 'safe', 'pizza', 'pasta', 'Loyola', 'cat', 'dog', 'rambler', 'Chicago', 'Pittsburgh']

def correct(guess):
    if guess in word:
        if guess not in guessed:
            print("Correct")
            return(True)
    else:
        if guess not in word and len(guess) == 1 and guess in 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ ':
            if guess not in guessed:
                print("Incorrect!")
                return(False)

print("Guess this word!")
print("You can input any letter from A to Z and the space key.")
wordnumber = random.randint(0, len(wordlist))
word = (wordlist[wordnumber])
guessed_letters = len(word) * ['_']
print(' '.join(guessed_letters))
while failures < allowed:
    guess = str(input("Guess a letter!"))
    if len(guess) != 1 or guess not in 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ ':
        print("That is not a letter, try again.")
    if guess in guessed:
        print("You have already guessed that letter, try again.")
    iscorrect = correct(guess)
    guessed = guessed, guess
    if iscorrect == True:
        for position, letter in enumerate(word):
            if letter == guess:
                guessed_letters[position] = letter
        print(' '.join(guessed_letters))
    if iscorrect == False:
        print("Wrong!")
        failures = failures+1
        guesses_left -= 1           # Number of guesses left
        print("You have", guesses_left , "guesses left.")

    if (guessed_letters == word):
        print('''
                You have successfully guessed the word!
            ''')
    else:
        print('''
                You have lost the game! 
            ''')
    break

Answer 1

游戏存在的原因是由于在第一个循环结束时调用的break。else还应该基于没有猜测的条件：

if (guessed_letters == word):
    print('''
            You have successfully guessed the word!
        ''')
    break
elif not guesses_left:
    print('''
            You have lost the game! 
        ''')
    break

关于“图形”。每次你得到一个错误的答案时，都会打印出来。我推荐使用if/else，而不是这里的两个if：

if iscorrect == True:
    for position, letter in enumerate(word):
        if letter == guess:
            guessed_letters[position] = letter
    print(' '.join(guessed_letters))
else:
    print("Wrong!")
    failures = failures+1
    guesses_left -= 1           # Number of guesses left
    print(Graphics[6-guesses_left])
    print("You have", guesses_left , "guesses left.")

Graphics[6-guesses_left]表示在Graphics中查找索引，该索引等于最初的猜测次数(6)减去剩余的猜测次数。