如何使用pegjs语法只解析注释？

Question

我写了一个pegjs语法，它可以解析任何js/c风格的注释。然而，这并不是很有效，因为我只设法捕获了注释本身，而忽略了其他所有内容。我应该如何改变这个语法，使其只解析任何类型的输入中的注释？

语法：

Start
  = Comment

Character
  = .

Comment
  = MultiLineComment
  / SingleLineComment

LineTerminator
  = [\n\r\u2028\u2029]

MultiLineComment
  = "/*" (!"*/" Character)* "*/"

MultiLineCommentNoLineTerminator
  = "/*" (!("*/" / LineTerminator) Character)* "*/"

SingleLineComment
  = "//" (!LineTerminator Character)*

输入：

/**
 * Trending Content
 * Returns visible videos that have the largest view percentage increase over
 * the time period.
 */

Other text here

错误

Line 5, column 4: Expected end of input but "\n" found.

Answer 1

在考虑注释(单行或多行)之前，您需要重构以专门捕获行内容，如下所示：

lines = result:line* {
  return result
}

line = WS* line:$( !'//' CHAR )* single_comment ( EOL / EOF ) { // single-comment line
  return line.replace(/^\s+|\s+$/g,'')
}
/ WS* line:$( !'/*' CHAR )* multi_comment ( EOL / EOF ) { // mult-comment line
  return line.replace(/^\s+|\s+$/g,'')
}
/ WS* line:$CHAR+ ( EOL / EOF ) { // non-blank line
  return line.replace(/^\s+|\s+$/g,'')
}
/ WS* EOL { // blank line
  return ''
}

single_comment = WS* '//' CHAR* WS*

multi_comment = WS* '/*' ( !'*/' ( CHAR / EOL ) )* '*/' WS*

CHAR = [^\n]
WS = [ \t]
EOF = !.
EOL = '\n'

它在运行时：

no comment here

single line comment // single-comment HERE

test of multi line comment /*

  multi-comment HERE

*/

last line

返回：

[
  "no comment here",
  "",
  "single line comment",
  "",
  "test of multi line comment",
  "",
  "last line"
]