我已经从一个带有igraph的数据框中创建了一个图表,显示了学生如何在职业课程之间移动。前两列是“From”和“To”,它们包含资格名称(顶点),每次学生第一次注册课程(From)和随后注册另一个课程(To)时都会出现。其余列包含与该特定学生的人口统计相关的值。
我想创建和绘制从每个单独的课程(788个独特的课程)到“OR”的运动的各个网络。我可以通过子图或过滤原始数据帧来实现这一点,但我认为需要一个循环或lapply函数,这样我就不需要重复键入公式。我还想为每个网络创建一个图和PDF。不幸的是,我的R技能还不够好,不足以让我弄清楚loop/lapply部分。
我的数据框的前两列概述如下(出于隐私原因,我删除了学生信息):
> dput(droplevels(head(df)))
structure(list(From = structure(c(5L, 1L, 6L, 4L, 2L, 3L), .Label = c("ADVANCED DIPLOMA OF ACCOUNTING",
"ADVANCED DIPLOMA OF CONVEYANCING", "ADVANCED DIPLOMA OF LEADERSHIP AND MANAGEMENT",
"ADVANCED DIPLOMA OF NETWORK SECURITY", "ADVANCED DIPLOMA OF POLICING",
"ADVANCED DIPLOMA OF VISUAL ARTS"), class = "factor"), To = structure(c(5L,
1L, 6L, 3L, 2L, 4L), .Label = c("DIPLOMA OF ACCOUNTING", "DIPLOMA OF EVENT MANAGEMENT",
"DIPLOMA OF INFORMATION TECHNOLOGY NETWORKING", "DIPLOMA OF LEADERSHIP AND MANAGEMENT",
"DIPLOMA OF POLICING", "DIPLOMA OF VISUAL ARTS"), class = "factor")), row.names = c(NA,
6L), class = "data.frame")然后创建图形,如下所示
g <- graph_from_data_frame(df, directed = TRUE, vertices = NULL)
E(g)$weight <- 1
g <- delete.edges(g, which(E(g)$weight <= 10))
g <- delete.vertices(g,which(degree(g)==0))然后,我通过一些颜色和标签的变化来使情节变得漂亮,并如下所示制作了一个pdf。
pdf("Qual_Pathways.pdf", width = 11.7, height = 16.5)
plot(g)
dev.off我如何才能使From或To中的每个唯一值循环通过,以生成一系列788网络,以显示与该特定资格的连接?我真的很感谢任何人的帮助,我似乎找不到任何东西。
发布于 2018-07-27 14:51:38
我想这可能就是你想要做的。首先,确保setwd到一个所有绘图将被转储到的目录。接下来,创建一个包含所有ego图的对象,即只包含连接到特定节点的节点:
library(igraph) # you must have loaded it earlier, but just in case
z <- make_ego_graph(g)这将生成一个igraph对象列表:
> z
[[1]]
IGRAPH 3e60c3b DNW- 4 4 --
+ attr: name (v/c), salary_income (e/n), other_income (e/n), survey_weights (e/n), weight
| (e/n)
+ edges from 3e60c3b (vertex names):
[1] 1->1 2->1 4->1 6->1
[[2]]
IGRAPH 3e60c3b DNW- 2 2 --
+ attr: name (v/c), salary_income (e/n), other_income (e/n), survey_weights (e/n), weight
| (e/n)
+ edges from 3e60c3b (vertex names):
[1] 1->1 2->1
...
[[7]]
IGRAPH 3e60c3c DNW- 3 2 --
+ attr: name (v/c), salary_income (e/n), other_income (e/n), survey_weights (e/n), weight
| (e/n)
+ edges from 3e60c3c (vertex names):
[1] 3->0 5->0您可以将所有7个ego网络转储到如下文件中:
jpeg(filename="EgoGraph%03d.jpeg")
for (i in 1:length(z)) { plot(z[[i]]) }
dev.off()现在去看看你setwd到的目录,将会有EgoGraph001.jpeg到EgoGraph007.jpeg。如果您对整个数据集执行此操作,并且它有788个节点,那么它将在该目录中提供788个绘图。
https://stackoverflow.com/questions/51551082
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