我真的需要你的帮助。我必须从SQL表中获取一些特定顺序的数据。所有数据都应该按KeyID按降序排序,但如果在第二列中有一些数据相同的行,则必须用另一行分隔它们。
例如,我们有这样的表:
KeyID UserID
1 15
2 17
3 19
4 19
5 15
6 17
7 17在结果表中,它应该是
KeyID UserID
7 17
5 15
6 17
4 19
2 17
3 19
1 15有没有办法做到这一点?
发布于 2017-01-17 21:43:33
这不会产生您想要的类型,但它应该扩展keyid:
order by row_number() over (partition by userId order by keyid desc),
keyid desc发布于 2017-01-17 21:51:56
这应该适用于最多有2个连续记录共享相同UserID的简单情况
SELECT KeyID, UserID
FROM (
SELECT KeyID, UserID,
rn, COUNT(*) OVER (PARTITION BY UserID, grp ORDER BY KeyID DESC) AS rnk
FROM (
SELECT KeyID, UserID,
ROW_NUMBER() OVER (ORDER BY KeyID DESC) AS rn,
ROW_NUMBER() OVER (ORDER BY KeyID DESC) -
ROW_NUMBER() OVER (PARTITION BY UserID
ORDER BY KeyID DESC) AS grp
FROM mytable) AS t) AS x
ORDER BY rn + rnk, KeyID 发布于 2017-01-17 22:32:01
下面的查询运行良好,符合您的预期结果。
WITH TEMP AS(
SELECT *,
ROW_NUMBER() OVER(PARTITION BY USERID ORDER BY KEYID DESC)ROW,
ROW_NUMBER()OVER(ORDER BY KEYID DESC)ROW1
FROM USERS
)
SELECT KEYID,USERID
FROM (
SELECT KEYID,USERID,ROW1,ROW FROM TEMP
WHERE ROW<>2
UNION
SELECT KEYID,USERID,ROW1+1 ROW1, ROW FROM TEMP
WHERE ROW=2
)B
ORDER BY ROW1 ASC下面是我的输出:

https://stackoverflow.com/questions/41698613
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