Easy Jaydata示例失败

Question

我正在学习本教程：

http://jaydata.org/tutorials/creating-a-stand-alone-web-application

因此，在包含以下内容之后：

<script src="jquery-1.12.4.min.js"></script>
<script src="jaydata-1.5.5-rc/jaydata.js"></script>

我正在尝试运行这个示例代码(我复制并粘贴了它)：

$data.Entity.extend("$org.types.Department", {
    Id: { type: "int", key: true, computed: true },
    Name: { type: "string", required: true },
    Address: { type: "string" },
    Employees: { type: "Array", elementType: "$org.types.Employee", inverseProperty: "Department" }
});
alert($data.Entity.Department);
$data.Entity.extend("$org.types.Employee", {
    Id: { type: "int", key: true, computed: true },
    FirstName: { type: "string", required: true },
    LastName: { type: "string", required: true },
    Department: { type: "$org.types.Department", inverseProperty: "Employees" }
});

$data.EntityContext.extend("$org.types.OrgContext", {
    Department: { type: $data.EntitySet, elementType: $org.types.Department },
    Employee: { type: $data.EntitySet, elementType: $org.types.Employee }
});

但在浏览器中，我收到错误消息，即"$org.types.Department“未定义。这让我抓狂，因为我完全按照简单的教程所说的去做。

有什么建议吗？

Answer 1

JayData 1.5.x不再使用全局变量，因此当您定义新类型时，请将其放入变量并在elementType中引用该变量。

var departmentType = $data.Entity.extend("$org.types.Department", ...
var employeeType = $data.Entity.extend("$org.types.Employee", ...

$data.EntityContext.extend("$org.types.OrgContext", {
    Department: { type: $data.EntitySet, elementType: departmentType  },
    Employee: { type: $data.EntitySet, elementType: employeeType }
});