Bash脚本在for循环后不能继续

Question

我正在试着在bash中做一个mac Clippy。下面是我的一些代码：

say "Hello there!"

declare -a assist_array=()

while true; do
  if pgrep -xq -- "Mail"; then
      assist_array+=('It looks like your trying to send an email. Would you like some help?')
  fi

  if pgrep -xq -- "Notes"; then
      assist_array+=('It looks like your trying to take a note. Would you like some help?')
  fi

  arraylength=${#assist_array[@]}
  for (( i=0; i<${arraylength}+1; i++ )); do
    echo ${assist_array[i]}
    say ${assist_array[i]}
    assist_array=()
  done

done

当我打开邮件时，它会回显并说："It looks like your trying to send an email. Would you like some help?"然后换一行。我打开了邮件和便笺。我如何才能让它继续扫描打开的应用程序，而不是陷入for循环？

Answer 1

在循环期间，您正在清空数组。因此，当尝试下一次迭代时，${assist_array[i]}中没有要打印的内容。如果需要清空数组，请在循环结束后执行。

此外，数组索引从0到length-1，而不是从1到length。通常，您应该引用可能包含多个单词的变量。

for (( i=0; i<${arraylength}; i++ )); do
    echo "${assist_array[i]}"
    say "${assist_array[i]}"
done
assist_array=()

Answer 2

say "Hello there!"

declare -a assist_array=()

while true; do
  if pgrep -xq -- "Mail"; then
      assist_array+=('It looks like your trying to send an email. Would you like some help?')
  fi

  if pgrep -xq -- "Notes"; then
      assist_array+=('It looks like your trying to take a note. Would you like some help?')
  fi

  arraylength=${#assist_array[@]}
  for (( i=0; i<${arraylength}; i++ )); do
    echo ${assist_array[i]}
    say ${assist_array[i]}    
  done
  assist_array=()
done

上面的代码应该可以为你工作。问题是数组是从零开始的，所以您对assist_array2的引用实际上是一个空字符串。当你没有传递任何东西给"say“时，它将读取stdin。

此外，正如其他答案(显式或隐式地)指出的那样，您正在初始化for循环中的数组。你不应该这样做，因为你还没有读完它。

所以，基本上，你只是坚持等待stdin。您可以按Ctrl-D来结束当前程序上的stdin输入。