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R正确使用Grouping Likert
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Stack Overflow用户
提问于 2017-01-17 01:27:33
回答 1查看 124关注 0票数 0

我正在尝试让分组选项起作用。当我选择分组时,我得到了错误的数据。以下是我的代码

代码语言:javascript
复制
> likert(GroupCD[16])
  Item Strongly Disagree Disagree  Neutral    Agree Strongly Agree
1  Q16                 0        0 10.71429 46.42857       42.85714
> likert(GroupCD[16],grouping = GroupCD$Group)
  Group Item Strongly Disagree Disagree  Neutral Agree Strongly Agree
1     C  Q16          6.666667 33.33333 60.00000     0              0
2     D  Q16         15.384615 61.53846 23.07692     0              0

因为可以看到分组分隔时的值是错误的,或者我可能(也可能)使用了错误的值。

以下是group列

代码语言:javascript
复制
> print(GroupCD$Group)
 [1] "C" "C" "C" "C" "C" "C" "C" "C" "C" "C" "C" "C" "C" "C" "C" "D" "D" "D" "D" "D" "D" "D" "D" "D" "D" "D" "D" "D"

有什么建议吗?

编辑:这里是GroupCD16

代码语言:javascript
复制
    "Q16"
    "1" "Strongly Agree"
    "2" "Strongly Agree"
    "3" "Strongly Agree"
    "4" "Strongly Agree"
    "5" "Agree"
    "6" "Agree"
    "7" "Strongly Agree"
    "8" "Strongly Agree"
    "9" "Agree"
    "10"    "Strongly Agree"
    "11"    "Strongly Agree"
    "12"    "Neutral"
    "13"    "Strongly Agree"
    "14"    "Agree"
    "15"    "Agree"
    "16"    "Neutral"
    "17"    "Strongly Agree"
    "18"    "Strongly Agree"
    "19"    "Agree"
    "20"    "Agree"
    "21"    "Agree"
    "22"    "Agree"
    "23"    "Agree"
    "24"    "Strongly Agree"
    "25"    "Agree"
    "26"    "Neutral"
    "27"    "Agree"
    "28"    "Agree"
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回答 1

Stack Overflow用户

回答已采纳

发布于 2017-02-11 06:38:55

所以我可以结束这个:显然这是R工作区/会话(??)中的垃圾问题。一旦我用一个新的开始,一切都很好

票数 0
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/41681840

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