我以前问过这个问题,但我仍然卡住了,无法将参数放入SQL查询中。
Public Function testInsert(tableName As String, dType As String, role As String,
FiscalYear As String)
Dim cmd As ADODB.Command
Dim conn As ADODB.connection
Dim prm As ADODB.Parameter
Dim connectionString As String
Dim SQL As String
Set conn = New ADODB.connection
Set cmd = New ADODB.Command
DBPath = "path\to\file.xlsm"
connectionString = "Provider=MSDASQL.1;DSN=Excel Files;DBQ=" & DBPath &";HDR=Yes';"
SQL = "INSERT INTO [" & tableName & "$] ([Year], [Type], [role]) VALUES (p1, p2, p3)"
'Open connection
conn.Open connectionString
'Set command text
cmd.CommandText = SQL
cmd.CommandType = adCmdText
'Set connection
cmd.ActiveConnection = conn
'Set paramters in SQL query
Set prm = cmd.CreateParameter("p1", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("p1").Value = 1
Set prm = cmd.CreateParameter("p2", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("p2").Value = 2
Set prm = cmd.CreateParameter("p3", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("p3").Value = 3
cmd.Execute
conn.Close
End Function我在excel-2010中使用VBA,并且在我的计算机上对外部excel文件运行查询。我得到的参数太少,预期会有三个错误。
请注意,如果值是字符串文字,则此代码可以工作,因此问题出在参数上。
发布于 2018-07-27 22:58:58
您没有遵循昨天的回复:(您不需要这个Prm变量,但是如果您使用了它,那么您应该为参数使用一个变量。
Public Function testInsert(tableName As String, dType As String, role As String,
FiscalYear As String)
Dim cmd As ADODB.Command
Dim conn As ADODB.connection
Dim prm1 As ADODB.Parameter
Dim prm2 As ADODB.Parameter
Dim prm3 As ADODB.Parameter
Dim connectionString As String
Dim SQL As String
Set conn = New ADODB.connection
Set cmd = New ADODB.Command
DBPath = "path\to\file.xlsm"
connectionString = "Provider=MSDASQL.1;DSN=Excel Files;DBQ=" & DBPath &";HDR=Yes';"
SQL = "INSERT INTO [" & tableName & "$] ([Year], [Type], [role]) VALUES (?, ?, ?)"
'Open connection
conn.Open connectionString
'Set command text
cmd.CommandText = SQL
cmd.CommandType = adCmdText
'Set connection
cmd.ActiveConnection = conn
'Set paramters in SQL query
Set prm1 = cmd.CreateParameter("@p1", adInteger, adParamInput)
cmd.Parameters.Append prm1
cmd.Parameters("@p1").Value = 1
Set prm2 = cmd.CreateParameter("@p2", adInteger, adParamInput)
cmd.Parameters.Append prm2
cmd.Parameters("@p2").Value = 2
Set prm3 = cmd.CreateParameter("@p3", adInteger, adParamInput)
cmd.Parameters.Append prm3
cmd.Parameters("@p3").Value = 3你根本不需要那些prm1,prm2,prm3:
'Set paramters in SQL query
cmd.Parameters.Append cmd.CreateParameter("@p1", adInteger, adParamInput)
cmd.Parameters.Append cmd.CreateParameter("@p2", adInteger, adParamInput)
cmd.Parameters.Append cmd.CreateParameter("@p3", adInteger, adParamInput)
cmd.Parameters("@p1").Value = 1
cmd.Parameters("@p2").Value = 2
cmd.Parameters("@p3").Value = 3发布于 2018-07-27 22:32:00
名称参数在开头带有'@‘,如@p1
Public Function testInsert(tableName As String, dType As String, role As String,
FiscalYear As String)
Dim cmd As ADODB.Command
Dim conn As ADODB.connection
Dim prm As ADODB.Parameter
Dim connectionString As String
Dim SQL As String
Set conn = New ADODB.connection
Set cmd = New ADODB.Command
DBPath = "path\to\file.xlsm"
connectionString = "Provider=MSDASQL.1;DSN=Excel Files;DBQ=" & DBPath &";HDR=Yes';"
SQL = "INSERT INTO [" & tableName & "$] ([Year], [Type], [role]) VALUES (@p1, @p2, @p3)"
'Open connection
conn.Open connectionString
'Set command text
cmd.CommandText = SQL
cmd.CommandType = adCmdText
'Set connection
cmd.ActiveConnection = conn
'Set paramters in SQL query
Set prm = cmd.CreateParameter("@p1", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("@p1").Value = 1
Set prm = cmd.CreateParameter("@p2", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("@p2").Value = 2
Set prm = cmd.CreateParameter("@p3", adInteger, adParamInput)
cmd.Parameters.Append prm
cmd.Parameters("@p3").Value = 3
cmd.Execute
conn.Close
End Functionhttps://stackoverflow.com/questions/51560008
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