channel()缺少1个必需的位置参数

Question

class Television(object):

    def __init__(self, lst):
        self.lst = lst

    def channel(self, number):
        print("You are currently tuning into" + self.lst[number-1])


def volume(reduce, loudness=0):
    loudness -= reduce
    return loudness


def main():
    channel = ['News','Sport','Movie','Music','Kids']
    TV = Television(channel)
    numbers = int(input("What do u want to watch?"))
    watch = Television.channel(numbers)
    reduce = int(input("Too loud? Reduce volume!"))
    adjust = Television(reduce)

main()

input("Press enter to exit")

如上面的代码所示，channel方法只需要1个参数，即number。但是，当我调用Television.channel(numbers) (其中numbers是供用户输入的值)时，它返回以下错误，如标题中所示。我是不是漏掉了什么？

Answer 1

您需要在实例TV上调用channel()方法

class Television(object):
    def __init__(self, lst):
        self.lst = lst

    def channel(self, number):
        print("You are currently tuning into " + self.lst[number-1])

def main():
    channels = ['News', 'Sport', 'Movie', 'Music', 'Kids']
    TV = Television(channels)
    number = int(input("What do u want to watch? "))
    watch = TV.channel(number)    

main()

input("Press enter to exit ")

运行上面的代码：

What do u want to watch? 3
You are currently tuning into Movie
Press enter to exit 
>>>