我想创建一个有4列的div,但是当屏幕在xs上时,我想居中显示任何内容。下面是我的代码:
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet"/>
<div class="row">
<div class="container">
<div class="col-xs-6 col-xs-offset-3 col-sm-3 col-md-3">
<img src="http://placehold.it/200x200" class="img-responsive" />
</div>
<div class="col-xs-6 col-xs-offset-3 col-sm-3 col-md-3">
<img src="http://placehold.it/200x200" class="img-responsive" />
</div>
<div class="col-xs-6 col-xs-offset-3 col-sm-3 col-md-3">
<img src="http://placehold.it/200x200" class="img-responsive" />
</div>
<div class="col-xs-6 col-xs-offset-3 col-sm-3 col-md-3">
<img src="http://placehold.it/200x200" class="img-responsive" />
</div>
</div>
</div>
但是在默认视图中,它显示了xs-6,所以我得到了2列。我不知道为什么,因为我将我的列设置为md-3
发布于 2017-06-30 14:00:18
您必须使用col-*-offset-0类覆盖较低的偏移量:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet"/>
<div class="row">
<div class="container">
<div class="col-xs-6 col-xs-offset-3 col-sm-3 col-sm-offset-0 col-md-3 col-md-offset-0">
<img src="http://placehold.it/200x200" class="img-responsive" />
</div>
<div class="col-xs-6 col-xs-offset-3 col-sm-3 col-sm-offset-0 col-md-3 col-md-offset-0">
<img src="http://placehold.it/200x200" class="img-responsive" />
</div>
<div class="col-xs-6 col-xs-offset-3 col-sm-3 col-sm-offset-0 col-md-3 col-md-offset-0">
<img src="http://placehold.it/200x200" class="img-responsive" />
</div>
<div class="col-xs-6 col-xs-offset-3 col-sm-3 col-sm-offset-0 col-md-3 col-md-offset-0">
<img src="http://placehold.it/200x200" class="img-responsive" />
</div>
</div>
</div>
https://stackoverflow.com/questions/44839423
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