在以下Python代码中:
keyboards = [3, 1]
drivers = [5, 2, 8]
upper_limit = 10
sums = [k + d for k in keyboards for d in drivers if (k + d) <= upper_limit]我想将k+d的结果存储在列表理解中,以便在列表理解中引用它。在Python3中是可能的吗?
我知道我们可以做到以下几点:
sums = []
for k in keyboards:
for d in drivers:
s = k + d
if s <= upper_limit:
sums.append(s)但是我希望避免append操作的副作用。
发布于 2017-07-09 01:22:48
在列表理解中,只有for循环可以为新名称赋值,所以如果你需要一个“局部”变量来引用一个计算,你需要想办法添加一个额外的循环。
您可以在计算k + d的单个元素元组上添加另一个循环
sums = [kd for k in keyboards for d in drivers for kd in (k + d,) if d <= upper_limit]或者,您也可以使用生成器表达式:
sums = [kd for kd in (k + d for k in keyboards for d in drivers) if kd <= upper_limit]在后一种情况下,您可以先将该表达式存储为单独的变量:
kd_calc = (k + d for k in keyboards for d in drivers)
sums = [kd for kd in kd_calc if kd <= upper_limit]演示:
>>> keyboards = [3, 1]
>>> drivers = [5, 2, 8]
>>> upper_limit = 10
>>> [kd for k in keyboards for d in drivers for kd in (k + d,) if d <= upper_limit]
[8, 5, 11, 6, 3, 9]
>>> [kd for kd in (k + d for k in keyboards for d in drivers) if kd <= upper_limit]
[8, 5, 6, 3, 9]
>>> kd_calc = (k + d for k in keyboards for d in drivers)
>>> [kd for kd in kd_calc if kd <= upper_limit]
[8, 5, 6, 3, 9]https://stackoverflow.com/questions/44988861
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