Python 3 threading.enumerate()异常

Question

我正在编写基于django的web，我的应用程序就在这里运行。用户传递一些参数，应用程序就会在自己的线程中启动。出于调试目的，我希望将所有活动线程打印到控制台。我使用python线程模块和以下代码：

import threading

def some_func():
    print(threading.enumerate())
    .
    .
    .

此调用会导致以下异常：

Traceback (most recent call last):
  File "C:\Python34\lib\site-packages\django\core\handlers\exception.py", line 39, in inner
    response = get_response(request)
  File "C:\Python34\lib\site-packages\django\core\handlers\base.py", line 187, in _get_response
    response = self.process_exception_by_middleware(e, request)
  File "C:\Python34\lib\site-packages\django\core\handlers\base.py", line 185, in _get_response
    response = wrapped_callback(request, *callback_args, **callback_kwargs)
  File "C:\Users\bakajsa\AppData\Local\Programs\Git\mysite\my_project\views.py", line 90, in some_func
    print(threading.enumerate())
  File "C:\Python34\lib\threading.py", line 824, in __repr__
    self.is_alive() # easy way to get ._is_stopped set when appropriate
  File "C:\Python34\lib\threading.py", line 1120, in is_alive
    self._wait_for_tstate_lock(False)
  File "C:\Python34\lib\threading.py", line 1076, in _wait_for_tstate_lock
    assert self._is_stopped
AssertionError

你知道会出什么问题吗？

根据文档：

threading.enumerate()

返回当前活动的所有Thread对象的列表。该列表包括守护线程、由current_thread()创建的虚拟线程对象和主线程。它不包括已终止的线程和尚未启动的线程。

Answer 1

我想这可能是打印的问题

试试这个：

for thread in threading._enumerate(): print(thread.name)