我有一个数据框d,像这样:
d <- data.frame("name" = c("pippo","pluto","paperino"),
"id" = c(1,2,3),"count" = c(10,20,30),
"pvalue"=c(0.01,0.02,0.05),
geneRatio=c(0.5,0.8,0.2),
type=c("KEGG","Reactome","Reactome"))我使用ggplot库绘制了一个点图:
ggplot(data = d,aes(geneRatio,name,size=count,colour = pvalue)) +
geom_point()+
ggtitle("Significantly Pathways") +
xlab("Gene Ratio") +
ylab("Pathways")+
theme(axis.text.y = element_text(color=d$type))这就是目前的情节

我想添加到图例中的“类型”的信息包含在数据帧d。我想有一个新的项目,在图例中的颜色红色=反应和颜色black= KEGG
发布于 2017-07-10 21:59:38
不是说这是个好主意,但是你可以添加一个无意义的geom来强制添加一个向导:
d <- data.frame("name" = c("pippo","pluto","paperino"),
"id" = c(1,2,3),
"count" = c(10,20,30),
"value"=c(0.01,0.02,0.05),
geneRatio=c(0.5,0.8,0.2),
type=c("KEGG","Reactome","Reactome")
)
library(ggplot2)
ggplot(data = d, aes(geneRatio,name,colour = pvalue)) +
geom_point(aes(size=count))+
geom_polygon(aes(geneRatio,name,fill = type)) +
ggtitle("Significantly Pathways") +
xlab("Gene Ratio") +
ylab("Pathways") +
scale_fill_manual(values = c('Reactome'='red', 'KEGG'='black')) +
theme(axis.text.y = element_text(color=d$type))

geom_polygon可能无法处理您的实际数据,并且您可能找不到合适的“无意义”geom。我同意@zx8754,一个方面会更清楚:
ggplot(data = d, aes(geneRatio,name,colour = pvalue)) +
geom_point(aes(size=count)) +
ggtitle("Significantly Pathways") +
xlab("Gene Ratio") +
ylab("Pathways") +
facet_grid(type ~ ., scales = 'free_y', switch = 'y')

发布于 2017-07-10 21:59:21
您可以使用annotate完成此操作,但这需要一点手动操作。
ggplot(data = d, aes(geneRatio, name, size = count, colour = pvalue)) +
geom_point() +
ggtitle("Significantly Pathways") +
xlab("Gene Ratio") +
ylab("Pathways")+
theme(axis.text.y = element_text(color=d$type)) +
annotate("text", x = 0.25, y = 3.5, label = "Reactome", color = "red") +
annotate("text", x = 0.25, y = 3.4, label = "KEGG", color = "black")

https://stackoverflow.com/questions/45013599
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