Php落在特定的季度

Question

很抱歉，我目前在这一部分遇到了问题。我的日期格式是Y-m-d

$date1 = '2016-03-1';
$date2 = '2016-07-1';
$date3 = '2016-10-1';
$date4 = '2016-12-1';

如果今天是2016-8-12，那么它应该落在$date3，因为它是下一段时间。我尝试使用if条件，但它只适用于第一个条件。你能在这方面给我一些启发吗？

我的代码有点像这样

$today = date("2016-07-29");
if(strtotime($date1) < strtotime($today)){
        $next_accrual_date = $date1;
        $date_condition = 'condition 1';
    }else
    if(strtotime($date2) <   strtotime($today)){
        $next_accrual_date = $date2;
        $date_condition = 'condition 2';
    }else
    if(strtotime($date3) <  strtotime($today)){
        $next_accrual_date = $date3;
        $date_condition = 'condition 3';
    }else
    if(strtotime($date4) <  strtotime($today)){
        $next_accrual_date = $date4;
        $date_condition = 'condition 4';
    }
echo $next_accrual_date." falls to ".$date_condition;

Answer 1

实现此目的的一种方法是

<?php
$dates = array();
$dates[] = '2016-03-1';
$dates[] = '2016-07-1';
$dates[] = '2016-10-1';
$dates[] = '2016-12-1';

usort($dates, "cmp");

function cmp($a, $b){ 
    return strcmp($a, $b); 
}

foreach($dates as $date){
  if($date > "2016-08-12"){
    echo $date;
    break;
  } 
}

//print_r($dates);

?>

现场演示：https://eval.in/621460

这将给出输出：

 2016-10-1

Answer 2

    $today = strtotime(date('Y-m-d'));

    $currentYear = date('Y');
    $dates = ['q1' => strtotime($currentYear.'-03-1'), 
                'q2' => strtotime($currentYear.'-07-1'), 
                'q3' => strtotime($currentYear.'-10-1'), 
                'q4' => strtotime($currentYear.'-12-1')];

    foreach ($dates as $qName => $qDate) {
        if ($qDate > $today) {
            return "$qDate falls to $qName";
        }
    }

Answer 3

只需将您的比较从<更改为>：

$today = date("2016-07-29");
if(strtotime($date1) > strtotime($today)){
    $next_accrual_date = $date1;
    $date_condition = 'condition 1';
}else ...
echo $next_accrual_date." falls to ".$date_condition;

它会起作用的。目前，您查看今天是否大于第一季度的日期，然后打破if。但是在“2016-03-1”之后的每个日期都会出现这种情况。这就是为什么你总是得到条件1的原因。