我有一段sql
SELECT pd.id, pd.title, pd.fname, pd.lname, pd.DOB, pd.phone_home, pd.phone_biz, pd.phone_contact, pd.phone_cell, pd.sex, pd.email, pd.pid, f.form_id, ldf1.field_value AS autoleaxis, ldf2.field_value AS autolecyl
FROM patient_data pd
LEFT JOIN forms f ON pd.pid = f.pid
LEFT JOIN `lbf_data` ldf1 ON ldf1.form_id = f.form_id
LEFT JOIN `lbf_data` ldf2 ON ldf1.form_id = ldf2.form_id
WHERE (
f.form_name = 'Opthalmology'
AND ldf1.field_id = 'autoleaxis'
AND ldf2.field_id = 'autolecyl'
)
OR (
f.form_id IS NULL
AND ldf1.field_id IS NULL
AND ldf2.field_id IS NULL
)
ORDER BY pd.pid这是针对MySQL数据库的。它工作得很好,除了在某些情况下,它会为每个人返回一个以上的记录,因为他们有多个form_id。如何限制它,使其只返回此人拥有的最高form_id的记录,如果没有,则将form_id设置为null。谢谢
发布于 2018-01-12 07:38:55
您可以在LEFT JOIN中使用子查询,如下所示:
SELECT *
FROM patient_data pd
LEFT JOIN
(
select max(form_id) as form_id, pid, form_name
from forms as f2
) as f
ON pd.pid = f.pid
LEFT JOIN `lbf_data` ldf1 ON ldf1.form_id = f.form_id
LEFT JOIN `lbf_data` ldf2 ON ldf1.form_id = ldf2.form_id
WHERE (
f.form_name = 'Opthalmology'
AND ldf1.field_id = 'autoleaxis'
AND ldf2.field_id = 'autolecyl'
)
OR (
f.form_id IS NULL
AND ldf1.field_id IS NULL
AND ldf2.field_id IS NULL
)
ORDER BY pd.pid您可以在here中进行测试
https://stackoverflow.com/questions/48217215
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